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Viktor [21]
3 years ago
12

Which is the most accurate description of compounds?

Chemistry
1 answer:
baherus [9]3 years ago
3 0

Answer: c.They have a unique set of properties that can be used as identifiers.

Explanation:

Compound is a pure substance which is made from atoms of different elements combined together in a fixed ratio by mass.

Compounds can be decomposed into simpler constituents using chemical reactions.

Example: Water (H_2O)

2H_2O\rightarrow 2H_2+O_2

Compounds have different properties than the elements it is made up of.

Thus the most accurate description of compounds is that they have a unique set of properties that can be used as identifiers.

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Will give lots of points if answered correctly. Determine the kb for chloroform when 0.793 moles of solute in 0.758 kg changes t
Liono4ka [1.6K]

Answer: The value of K_{b} for chloroform is 3.62^{o}C/m when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.

Explanation:

Given: Moles of solute = 0.793 mol

Mass of solvent = 0.758

\Delta T_{b} = 3.80^{o}C

As molality is the number of moles of solute present in kg of solvent. Hence, molality of given solution is calculated as follows.

Molality = \frac{no. of moles}{mass of solvent (in kg)}\\= \frac{0.793 mol}{0.758 kg}\\= 1.05 m

Now, the values of K_b is calculated as follows.

\Delta T_{b} = i\times K_{b} \times m

where,

i = Van't Hoff factor = 1 (for chloroform)

m = molality

K_{b} = molal boiling point elevation constant

Substitute the values into above formula as follows.

\Delta T_{b} = i\times K_{b} \times m\\3.80^{o}C = 1 \times K_{b} \times 1.05 m\\K_{b} = 3.62^{o}C/m

Thus, we can conclude that the value of K_{b} for chloroform is 3.62^{o}C/m when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.

7 0
3 years ago
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