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Art [367]
4 years ago
13

•If I could have help on 11-16 that would be awesome.•

Mathematics
1 answer:
oee [108]4 years ago
3 0
Hope this can help you. I tried to solve each one out and I tried to write notes on how I got the equation and the answer. Message me if you can't read something, my handwriting tends to be messy :)

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Determine the number of real solutions each quadratic equation has. y = 12x2 - 9x 4 real solution(s) 10x y = -x2 2 real solution
nordsb [41]

All the given equations have 2 real solutions except for equation 4 which has only one real root.

<h3>What is a quadratic equation?</h3>

A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is  ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.

The given quadratic equation

y = 12x^2 - 9x+ 4

where, a = 12, b = -9 and c = 4

x = -b + \sqrt{b^2 - 4ac} /2a

x = -(-9)+ \sqrt{(-9)^2 - 4(12)(4)} /2(12)

x = 1.063 or -0.313

Second Equation

10x +y = -x^2 +2 \\y = x^{2} +10x - 2

where, a = 1, b = 10, c = -2

substitute the values into the equation

x = -b + \sqrt{b^2 - 4ac} /2a

-10 + \sqrt{10^2 - 4(1)(-2)} /2(1)

x = 0.195 or -10.195

Third Equation

4y - 7 = 5x^2 - x +2 +3y

y = 5x^{2} -x -5

where, a = 5, b = -1, c = - 5

x = -b + \sqrt{b^2 - 4ac} /2a

-(-1) + \sqrt{(-1)^2 - 4(5)(-5)} /2(5)

x = 0.905 or -0.55

Fourth Equation

y = (-x +4)^2 \\y = x^{2} -8x +16

where, a = 1, b = -8, c = 16

x = -b + \sqrt{b^2 - 4ac} /2a

x = -(-8) + \sqrt{(-8)^2 - 4(1)(16)} /2(1)

x = 4

Learn more about quadratic equations;

brainly.com/question/13197897

6 0
2 years ago
10 POINTS AND BRAINLIEST!
LUCKY_DIMON [66]

Answer:

A=bh=24*8=192

V=2(wl+hl+hw)=2·(4·3+15·3+15·4)=234

A=1311(big rectangle ---> (31-12)69)+2(12 x 23 ---> because of the two smaller rectangles=1311+552=1863

Step-by-step explanation:

algebra

7 0
4 years ago
Read 2 more answers
About 7% of the population of a large country is nervous around strangers. If two people are randomly selected, what is the prob
chubhunter [2.5K]

Answer:

Probability both are nervous around strangers = 0.0049

Probability at least one is nervous around strangers = 0.1302

Step-by-step explanation:

Let probability a person selected in the population is nervous around strangers = P

                                        P = 7%

                                        P = \frac{7}{100}

                                        P = 0.07

Let probability a person selected in the population is not nervous around strangers = P'

                                         P' = 1 - P

                                         P' = 1 - 0.07

                                         P' = 0.93

(i) probability of the first person selected is nervous around strangers = P

   probability of the second person selected is nervous around strangers = P

   Probability both are nervous around strangers = (P × P)

                                         = 0.07 × 0.07

                                         = 0.0049

(ii) Probability at least one is nervous around strangers = ( probability the first person is nervous around strangers AND the second person is not nervous around strangers ) OR ( probability the second person is nervous around strangers AND the first person is not nervous around strangers)

This implies,

Probability at least one is nervous around strangers = (P × P') or (P × P')

                                        = (0.07 × 0.93) + (0.07 × 0.93)

                                        = 0.0651 + 0.0651

                                        = 0.1302

5 0
4 years ago
andy mailed two packages. the first package weighed 2.48 pounds, and the second package weighed 2.6 pounds. andy said the first
rodikova [14]
The second package weighs more, 2.6 or 2.60 weighs more than 2.48
3 0
4 years ago
Read 2 more answers
I needs it the question asap
kirill [66]

Answer:

The pink box

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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