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skelet666 [1.2K]
3 years ago
7

A cubic object has a volume of 250 cm. What is its density if its mass is 5 points 257.3 g?

Chemistry
1 answer:
ira [324]3 years ago
8 0

Answer:

<h3>The answer is 1.03 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question

mass = 257.3 g

volume = 250 cm³

We have

density =  \frac{257.3}{250}  \\  = 1.0292

We have the final answer as

<h3>1.03 g/cm³</h3>

Hope this helps you

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<span>a. They produce ions when dissolved in water.

acids in water

</span>

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HA  --> H+  + A<span>-</span>

bases

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3 years ago
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What is the standard electrode potential for a galvanic cell constructed in the appropriate way from these two half-cells?
____ [38]

E

θ

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=

+

2.115

l

V

Cathode

Mg

2

+

/

Mg

Anode

Ni

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Explanation:

Look up the reduction potential for each cell in question on a table of standard electrode potential like this one from Chemistry LibreTexts. [1]

Mg

2

+

(

a

q

)

+

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l

e

−

→

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(

s

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Ni

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+

(

a

q

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+

2

l

e

−

→

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(

s

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−

E

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The standard reduction potential

E

θ

resembles the electrode's strength as an oxidizing agent and equivalently its tendency to get reduced. The reduction potential of a Platinum-Hydrogen Electrode under standard conditions (

298

l

K

,

1.00

l

kPa

) is defined as

0

l

V

for reference. [2]

A cell with a high reduction potential indicates a strong oxidizing agent- vice versa for a cell with low reduction potentials.

Two half cells connected with an external circuit and a salt bridge make a galvanic cell; the half-cell with the higher

E

θ

and thus higher likelihood to be reduced will experience reduction and act as the cathode, whereas the half-cell with a lower

E

θ

will experience oxidation and act the anode.

E

θ

(

Ni

2

+

/

Ni

)

>

E

θ

(

Mg

2

+

/

Mg

)

Therefore in this galvanic cell, the

Ni

2

+

/

Ni

half-cell will experience reduction and act as the cathode and the

Mg

2

+

/

Mg

the anode.

The standard cell potential of a galvanic cell equals the standard reduction potential of the cathode minus that of the anode. That is:

E

θ

cell

=

E

θ

(

Cathode

)

−

E

θ

(

Anode

)

E

θ

cell

=

−

0.257

−

(

−

2.372

)

E

θ

cell

=

+

2.115

Indicating that connecting the two cells will generate a potential difference of

+

2.115

l

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across the two cells.

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2 years ago
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Answer:

B.

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elements

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