<u>Given</u><u> </u><u>that</u><u> </u>
- Height of container is 20 inches .
- Radius of base is 10 inches .
<u>To</u><u> </u><u>Find</u><u> </u>
<u>Formul</u><u>a</u><u> </u>
- Volume of cylinder is πr²h
<u>Solu</u><u>tion</u><u> </u>
→ Volume = πr²h
<u>Usin</u><u>g</u><u> </u><u>π</u><u> </u><u>as</u><u> </u><u>3</u><u>.</u><u>1</u><u>4</u><u> </u>
→ 3.14 × 10 × 10 × 20 = Volume
→ 314 × 20 = Volume
→ <u>6</u><u>2</u><u>8</u><u>0</u><u> </u><u>inches²</u><u> </u><u>is</u><u> </u><u>the holding capacity of the</u><u> container</u><u>. </u><u> </u>
2 x minus 5 y = negative 5. y = two-fifths x + 1.
We take the equation
<span>x^2 -4x + y^2 + 6y + 12 = 0
and complete the square for x and y.
</span><span>x^2 -4x + 4 - 4 + y^2 + 6y + 9 - 9 + 12= 0</span>
<span> (x-2)^2 - 4 + (y+3)^2 - 9 = -12</span>
<span> <span>(x-2)^2+ (y+3)^2 = 1
Therefore the answer is </span></span><span>(x-2)^2+ (y+3)^2 = 1</span>
318,224,480
5 is in the ones place so u round up
Logbx-logby-2logbz
1/2ln2+3/2lnx+1/2lny
