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rosijanka [135]
4 years ago
13

Write a net ionic equation to show how codeine, c18h21o3n, behaves as a base in water.

Chemistry
1 answer:
Lera25 [3.4K]4 years ago
7 0

Actually, the ionic equation for this is a reversible equation since codeine is a weak base. Any weak base or weak acids do not completely dissociate which makes them a reversible process. The ionic equation for this case is:

<span>C18H21O3N  +  H3O+  </span><=> C18H21O3NH+ +  H2O 

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3 years ago
If element X has 59 protons, how many electrons does it have?
laiz [17]
If element X has 59 protons then element X has 59 electrons.

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3 years ago
Calculation of ph from hydrogen ion concentration what is the ph of a solution that has an h1 concentration of (a) 1.75 3 1025 m
faltersainse [42]
<h2>Solutions:</h2>

<u>Case a:</u> Finding pH for [H⁺] = 1.75 × 10⁻⁵ mol/L :

As we know pH is given as,

                                  pH  = -log [H⁺]

Putting value,

                                  pH  = -log [1.75 x 10⁻⁵]

                                 pH =  4.75

<u>Case b:</u> Finding pH for [H⁺] = 6.50 × 10⁻¹⁰ mol/L :

As we know pH is given as,

                                  pH  = -log [H⁺]

Putting value,

                                  pH  = -log [6.50 × 10⁻¹⁰]

                                 pH =  9.18

<u>Case c:</u> Finding pH for [H⁺] = 1.0 × 10⁻⁴ mol/L :

As we know pH is given as,

                                  pH  = -log [H⁺]

Putting value,

                                  pH  = -log [1.0 × 10⁻⁴]

                                 pH =  4

<u>Case d:</u> Finding pH for [H⁺] = 1.50 × 10⁻⁵ mol/L :

As we know pH is given as,

                                  pH  = -log [H⁺]

Putting value,

                                  pH  = -log [1.50 × 10⁻⁵]

                                 pH =  4.82

7 0
3 years ago
What sort of chemical hazard is thalidomide?
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3 0
3 years ago
Calculate ΔG∘rxn for the following reaction:4CO(g)+2NO2(g)→4CO2(g)+N2(g).Use the following reactions and given ΔG∘rxn values:A)
mihalych1998 [28]

Answer : The   value of \Delta G^o_{rxn} for the reaction is -1131.4 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

The given main reaction is,

4CO(g)+2NO_2(g)\rightarrow 4CO_2(g)+N_2(g)    \Delta G^o_{rxn}=?

The intermediate balanced chemical reaction will be,

(1) 2NO(g)+O_2(g)\rightarrow 2NO_2(g)     \Delta G^o_1=-72.6kJ

(2) 2CO(g)+O_2(g)\rightarrow 2CO_2(g)     \Delta G^o_2=-514.4kJ

(3) \frac{1}{2}O_2(g)+\frac{1}{2}N_2(g)\rightarrow NO(g)     \Delta G^o_3=87.6kJ

Now we will reverse the reaction 1, multiply the reaction 2 by 2, reverse and half the reaction 3 and then adding all the equations, we get :

(1) 2NO_2(g)\rightarrow 2NO(g)+O_2(g)     \Delta G^o_1=72.6kJ

(2) 4CO(g)+2O_2(g)\rightarrow 4CO_2(g)     \Delta G^o_2=2\times (-514.4kJ)=-1028.8kJ

(3) 2NO(g)\rightarrow O_2(g)+N_2(g)     \Delta G^o_3=-2\times 87.6kJ=-175.2kJ

The expression for \Delta G^o_{rxn} will be,

\Delta G^o_{rxn}=\Delta G^o_{1}+\Delta G^o_{2}+\Delta G^o_{3}

\Delta G^o_{rxn}=(72.6kJ)+(-1028.8kJ)+(-175.2kJ)

\Delta G^o_{rxn}=-1131.4kJ

Therefore, the value of \Delta G^o_{rxn} for the reaction is -1131.4 kJ

3 0
4 years ago
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