Ask question

Ask question

All categories

3 years ago

14

How many independent variables can you have during an experiment? A: 1 B: 2 C: as many as you would like D: the same amount as t

he number of controlled variables

2 answers:

lianna [129]3 years ago

3 0

Answer: a

Explanation: its 1

3241004551 [841]3 years ago

3 0

Answer:

A: 1 independent variable

Explanation:

its the variable you're changing to see the impacts it has on different variables

You might be interested in

How many photons are produced in a laser pulse of 0.897 J at 407 nm?

Leona [35]

The relationship between energy of a single photon and its wavelength can be determined using the formula E=hc/lambda where E is energy, h is Planck's constant, c is the speed of light, and lambda is photons.

Before being able to solve for energy, need to convert nanometers to meters.

407 nm (1 m/1 x 10^9 nm) = 4.07 x 10^-7 m

Then plug in the values we know into the equation.
E h(Planck's constant) c(speed of light)
E = (6.63 x 10^-34 Js)(3 x 10^8 m/s) / 4.07 x 10^-7 m (lambda)

E=(0.000000000000000000000000000000000663js)(300,000,000m/s)=1.989×10^-25j/ms

E=1.989x10^-25j/ms /{divided by} 4.07x10^-7m = 4.8869779x10^-33 J (the meters cancel out)

E = 4.89 x 10^-33 J

This gives us the energy in Joules of a single photon. Now, we can find the number of photons in 0.897 J

0.897J / 4.89 x 10^-33 J = ((0.897 J) / 4.89) x ((10^(-33)) J) = 1.8343558 x 10^-34

1.83435583 × 10-34m4 kg2 / s4 photons

4 0

4 years ago

Becoming a physicist involves studying various subject matter, besides physics what subjects should be studied in college?

atroni [7]

Answer:

Crystallography, nanotechnology, biophotonics, condensed matter theory and solar energy.

Explanation:

Some other subjects that should be studied in college are crystallography, nanotechnology, biophotonics, condensed matter theory ,and solar energy. These may help you in the studying of a physicist.

Hope it helped brainiest plz

3 0

3 years ago

According to the following reaction, how many grams of water are produced in the complete reaction of 29.7 grams of ammonia? 4 N

Gnesinka [82]

<u>Answer:</u> The mass of water produced in the reaction is 47.25 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of ammonia = 29.7 g

Molar mass of ammonia = 17 g/mol

Putting values in equation 1, we get:

$\text{Moles of ammonia}=\frac{29.7g}{17g/mol}=1.75mol$

The given chemical reaction follows:

$4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g)$

By stoichiometry of the reaction:

4 moles of ammonia produces 6 moles of water.

So, 1.75 moles of ammonia will produce = $\frac{6}{4}\times 1.75=2.625mol$ of water.

Now, calculating the mass of water by using equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 2.625 moles

Putting values in equation 1, we get:

$2.625mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=47.25g$

Hence, the mass of water produced in the reaction is 47.25 grams.

3 0

3 years ago

How does natural selection change the traits of living things over long periods of time? *

WARRIOR [948]

The answer for this one is C . Organisms are always changing traits

8 0

3 years ago

Read 2 more answers

How many mL of 0.563 M HNO3 are needed to dissolve 7.83 g of BaCoz? 2HNO3(aq) + BaCO3(s) — Ba(NO3)2(aq) + H2O(1) + CO2(8) mL

Lorico [155]

Answer:

Volume of HNO₃ required = 140 mL

Explanation:

Given data:

Molarity of HNO₃ = 0.563 M

mass of BaCO₃ = 7.83 g

Volume of HNO₃ = ?

Solution:

First of all we will write the balance chemical equation

2HNO₃ + BaCO₃ → Ba(NO₃)₂ + H₂O + CO₂

Number of moles of BaCO₃ = mass / molar mass

Number of moles of BaCO₃ = 7.83 g / 197.34 g/mol

Number of moles of BaCO₃ = 0.04 mol

Now we compare the moles of BaCO₃ and HNO₃ .

BaCO₃ : HNO₃

1 : 2

0.04 : 2×0.04 = 0.08 mol

Volume of HNO₃ required = number of moles / Molarity

Volume of HNO₃ required = 0.08 mol / 0.563 mol/L

Volume of HNO₃ required = 0.14 L

0.14 × 1000 = 140 mL

8 0

3 years ago