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Ymorist [56]
3 years ago
14

How many independent variables can you have during an experiment? A: 1 B: 2 C: as many as you would like D: the same amount as t

he number of controlled variables
Chemistry
2 answers:
lianna [129]3 years ago
3 0

Answer: a

Explanation: its 1

3241004551 [841]3 years ago
3 0

Answer:

A: 1 independent variable

Explanation:

its the variable you're changing to see the impacts it has on different variables

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An unknown radioactive substance has a half-life of 3.20hours . If 46.2g of the substance is currently present, what mass A0 was
iogann1982 [59]

Answer:

a) a0 was 46.2 grams

b) It will take 259 years

c) The fossil is 1845 years old

Explanation:

<em>An unknown radioactive substance has a half-life of 3.20hours . If 46.2g of the substance is currently present, what mass A0 was present 8.00 hours ago?</em>

A = A0 * (1/2)^(t/h)

⇒ with A = the final amount = 46.2 grams

⇒ A0 = the original amount

⇒ t = time = 8 hours

⇒ h = half-life time = 3.2 hours

46.2 = Ao*(1/2)^(8/3.2)

Ao = 261.35 grams

<em>Americium-241 is used in some smoke detectors. It is an alpha emitter with a half-life of 432 years. How long will it take in years for 34.0% of an Am-241 sample to decay?</em>  

t = (ln(0.66))-0.693) * 432 = 259 years

It will take 259 years

<em>A fossil was analyzed and determined to have a carbon-14 level that is 80% that of living organisms. The half-life of C-14 is 5730 years. How old is the fossil?</em>

<em />

t = (ln(0.80))-0.693) * 5730 = 1845

The fossil is 1845 years old

7 0
3 years ago
Determine the density of gold if a 475.09g sample occupy a space of 24.6cm^3
Ira Lisetskai [31]

Answer:

The answer is

<h2>19.31 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}

From the question

mass of gold = 475.09g

volume = 24.6 cm³

The density of the gold is

density =  \frac{475.09}{24 .6}  \\  = 19.3126016...

We have the final answer as

<h3>19.31 g/cm³</h3>

Hope this helps you

6 0
3 years ago
Students performed a procedure similar to Part II of this experiment (Analyzing Juices for Vitamin C Content) as described in th
Elan Coil [88]

Students performed a procedure similar to Part II of this experiment (Analyzing Juices for Vitamin C Content) as described in the procedure section. Given that molarity of DCP is 9.98x10-4 M, it took 16.34 ml of DCP to titrate 10 mL of sample.

Amount of ascorbic acid = 0.050 L sample (0.01634 L DCP/0.01 L sample)( 9.98x10-4 mol DCP/L DCP)(1 mol Ascorbic acid/ 1mol DCP)(176.124 g/mol)(1000mg/1g)= 14.36 mg ascorbic acid

8 0
3 years ago
Read 2 more answers
Elements classified as metals, nonmetals, and metalloids. Can you use the periodic table to locate these groups of elements? Wha
Lemur [1.5K]

Based on the electronic configuration the elements are classified as metals, non metals and metalloids.

<u>Explanation:</u>

Periodic table consists of three major parts.

The left side consists of metals and the right side consists of non-metals and here Hydrogen element is the exception and in between those two regions we have metalloids, which has the dual character of both metals and non metals.

These elements can be grouped by means of its chemical properties and also  due to its outermost electronic configuration.

If the valence shell electrons are same they are categorized under same group.

3 0
3 years ago
Water, carbon, and nitrogen move through living and nonliving things on Earth through processes known as _____. A. transformatio
skelet666 [1.2K]
Hey there
_____________
The correct answer is:
Water, carbon, and nitrogen move through living and nonliving things on Earth through processes known as C. cycles .

________________
Hope this helps you
6 0
3 years ago
Read 2 more answers
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