Consider the reaction below.
1 answer:
Hey there!
I attached a screenshot of my chemistry notes from this year on equilibrium constants in particular. Feel free to reference this in the future if you wish.
Based on the information in my attachment, you could construct your constant like this:
![K_{eq} = \frac{[CaO][CO_{2}]}{[CaCO_{3}]}](https://tex.z-dn.net/?f=%20K_%7Beq%7D%20%3D%20%20%5Cfrac%7B%5BCaO%5D%5BCO_%7B2%7D%5D%7D%7B%5BCaCO_%7B3%7D%5D%7D%20)
I don't think it matters which order your reactants or products are in as long as you have them on the top and bottom where they need to be, so your answer will be B.
Hope this helped you out! :-)
I attached a screenshot of my chemistry notes from this year on equilibrium constants in particular. Feel free to reference this in the future if you wish.
Based on the information in my attachment, you could construct your constant like this:
I don't think it matters which order your reactants or products are in as long as you have them on the top and bottom where they need to be, so your answer will be B.
Hope this helped you out! :-)
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Answer : The reaction is endothermic.
Explanation :
Formula used :
where,
= change in temperature =
Q = heat involved in the dissolution of KCl = ?
m = mass = 0.500 + 50.0 = 50.5 g
c = specific heat of resulting solution =
Now put all the given value in the above formula, we get:
The heat involved in the dissolution of KCl is positive that means as the change in temperature decreases then the reaction is endothermic and as the change in temperature increases then the reaction is exothermic.
Hence, the reaction is endothermic.