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Mrrafil [7]
3 years ago
8

Convert 1.4×10^9km^3 into cubic meters

Physics
2 answers:
storchak [24]3 years ago
7 0

Explanation: Hi! here we have 1.4×10^9km^3 and want to write this quantity in meters.

First, a kilometer is one thousand meters, so 1km = 1000m, so 1km^{3} = (1000m)^{3}= 1000000000m^{3}. = 10^9 m^3

so changin this in our quantity we get 1.4×10^9km^3  = 1.4×10^9*10^9 m^3=1.4×10^18m^3

and there you hace the original quantity written in meters.

Vadim26 [7]3 years ago
3 0
1km=10^3 m,1km^3=10^9cubic metres answer is 1.4x10^18cubic meters
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How many orbitals are allowed in a subshell if the angular momentum quantum number for electrons in that subshell is 3?
svp [43]

Answer:

7 orbitals are allowed in a sub shell if the angular momentum quantum number for electrons in that sub shell is 3.

Explanation:

We that different values of m for a given l provide the total number of ways in which a given s, p,d and f sub shells in presence of magnetic field can be arranged in space along x, y ,z- axis or total number of orbitals into which a given subshell can be divided.

    Range for given l lies between -l to +l .

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4 0
3 years ago
I need help ASAP plzzzz
Fiesta28 [93]

Answer:

a) 1.75s b) 17.2 m/s (down)

Explanation:

d1= 15m d2= 0m (because it hits ground)

a= -9.81 m/s^2 t=???

Equation

the triangle means change in so d2-d1

Δd= v1 * t + 1/2 * a * t^2

0m-15m= v1*t + 1/2 a t^2

-15 m= 0m/s*t (goes away) + 1/2* a *t^2

-15mx2= t^2

-15mx2/a= t^2

Square root (-30/-9.81m/s^2)

t=1.75 s

b) now v2!!

Im going to use v2= v1 + a*t

v2= 0m/s + -9.81 x 1.75s

v2 = -17.2 m/s or you can say 17.2 m/s down!!!

7 0
3 years ago
What frequency is received by a person watching an oncoming ambulance moving at 110 km/h and emitting a steady 800-Hz sound from
Strike441 [17]

To develop this problem we will apply the concepts related to the Doppler effect. The frequency of sound perceive by observer changes from source emitting the sound. The frequency received by observer f_{obs} is more than the frequency emitted by the source. The expression to find the frequency received by the person is,

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v_s = 30.55m/s

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f_{obs} = 878Hz

Therefore the frequency receive by observer is 878Hz

8 0
3 years ago
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elena-s [515]
Formula from physics to get the answer.
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