Answer:gravity and friction
Explanation:Gravity to keep yourself on the ground and friction to not slide when are walking.
You've failed because you failing becomes a statement rather than it becoming fact or what actually happened.
The work done is 400 J
Explanation:
The work done by you in pushing the box along the slope is given by
![W=Fd](https://tex.z-dn.net/?f=W%3DFd)
where
F is the magnitude of the force applied
d is the distance covered by the box along the slope
Here we have the following:
F = 200 N is the magnitude of the force applied
is the distance covered, where
h = 1 m is the vertical rise
is the slope of the plane
Substituting and solving, we find
![W=F\frac{h}{sin \theta}=\frac{(200)(1)}{sin 30^{\circ}}=400 J](https://tex.z-dn.net/?f=W%3DF%5Cfrac%7Bh%7D%7Bsin%20%5Ctheta%7D%3D%5Cfrac%7B%28200%29%281%29%7D%7Bsin%2030%5E%7B%5Ccirc%7D%7D%3D400%20J)
Learn more about work:
brainly.com/question/6763771
brainly.com/question/6443626
#LearnwithBrainly
Your answer should be D
let me know if I got it wrong
Hope this helped!
Ans: Beat Frequency = 1.97HzExplanation:
The fundamental frequency on a vibrating string is
![f = \sqrt{ \frac{T}{4mL} }](https://tex.z-dn.net/?f=f%20%3D%20%20%20%5Csqrt%7B%20%5Cfrac%7BT%7D%7B4mL%7D%20%7D%20)
<span> -- (A)</span>
<span>here, T=Tension in the string=56.7N,
L=Length of the string=0.66m,
m= mass = 8.3x10^-4kg/m * 0.66m = 5.48x10^-4kg </span>
Plug in the values in Equation (A)
<span>so </span>
![f = \sqrt{ \frac{56.7}{4*5.48*10^{-4}*0.66} }](https://tex.z-dn.net/?f=f%20%3D%20%5Csqrt%7B%20%5Cfrac%7B56.7%7D%7B4%2A5.48%2A10%5E%7B-4%7D%2A0.66%7D%20%7D)
<span> = 197.97Hz </span>
<span>the beat frequency is the difference between these two frequencies, therefore:
Beat frequency = 197.97 - 196.0 = 1.97Hz
-i</span>