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Nutka1998 [239]
3 years ago
14

Why doesn't an object thrown in an upward direction fall the same distance in each time interval as it descends toward Earth? (A

).because it is falling toward the earth (B).because it is heavier than the air it is falling through (C).because it is accelerating (D).none of the above
Physics
1 answer:
Stels [109]3 years ago
4 0
I'm not that smart but I think it is c I really hope It helps
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A 40-w lightbulb connected to a 120-v source experiences a voltage surge that produces 132 v for a moment. by what percentage do
andrey2020 [161]
R=U^2/P=120*120/40=360 ohm
P2=U2^2/R=132*132/360=48.4 w
power increase ratio (48.4-40)/40=21%
3 0
2 years ago
A student uses the right-hand rule as shown.
m_a_m_a [10]

Answer: O:right

Explanation: In this case you place your finger on the current, and your fingers should curl showing the way, you must use your right hand in this case, otherwise that would mean the fingers on your left would bend way back, and snap off, (Not really lol,  just saying)

5 0
2 years ago
How is work calculated?
BartSMP [9]

Work is force times distance. If there's no distance, there's no work being done.

6 0
3 years ago
The world's most powerful laser is the LFEX laser in Japan. It can produce a 2 petawatt(2×10^15W) laser pulse that last for 1 ps
kogti [31]

Answer:

2.82942\times 10^{24}\ W\m^2

Explanation:

d = Diameter of spot = 30 μm

r = Radius of spot = \frac{d}{2}=\frac{30}{2}=15\ mu m

P = Power of the laser = 2\times 10^{15}\ W

A = Area = \pi r^2

Intensity is given by

I=\frac{P}{A}\\\Rightarrow I=\frac{2\times 10^{15}}{\pi\times (15\times 10^{-6})^2}\\\Rightarrow I=2.82942\times 10^{24}\ W/m^2

The light intensity within this spot is 2.82942\times 10^{24}\ W/m^2

8 0
3 years ago
A Red Rider bb gun uses the energy in a compressed spring to provide the kinetic energy for propelling a small pellet of mass 0.
Kay [80]

Answer:

a.6.5025 J

b.6.5025 J

Explanation:

We are given that

Mass of pellet,m=0.27 g=0.27\times 10^{-3} kg

1 kg=1000 g

Spring constant,k=1800 N/m

x=8.5 cm=8.5\times 10^{-2} m

1m=100 cm

a.Potential energy stored in the compressed spring  is given by

P.E=\frac{1}{2}kx^2

P.E=\frac{1}{2}(1800)(8.5\times 10^{-2})^2

P.E=6.5025 J

b.By using law of conservation of energy

P.E of spring=K.E of the pellet

K.E of the pellet=6.5025 J

6 0
3 years ago
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