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julsineya [31]
2 years ago
11

PLEASE HELP ME!!!!! You draw an arrow from left to right on a piece of paper and place the paper well behind a glass of water. Y

ou observe that the direction of the arrow appears reversed behind the water glass!
What conclusions can you draw from this experiment?


(1 point)


The arrow appears reversed because light is bent as it enters the water, and again as it exits. The two light paths cross, making the direction of the arrow appear crossed.

The arrow appears reversed because light is bent as it enters the water, and again as it exits. The two light paths cross, making the direction of the arrow appear crossed.


The arrow appears reversed because light is reflected by the glass of water. Light is reflected so much that the arrow appears to face the other direction.

The arrow appears reversed because light is reflected by the glass of water. Light is reflected so much that the arrow appears to face the other direction.


It is not possible for the arrow to appear reversed behind a glass of water. The most likely explanation is that a mistake was made during the experiment.

It is not possible for the arrow to appear reversed behind a glass of water. The most likely explanation is that a mistake was made during the experiment.


The arrow appears reversed because light is split as it enters the water, and combines again as it exits the water. When the light re-combines, the arrow appears to be flipped.

Physics
1 answer:
julia-pushkina [17]2 years ago
7 0

Answer:

I think it is the first one: <u>The arrow appears reversed because light is bent as it enters the water, and again as it exits. The two light paths cross, making the direction of the arrow appear crossed.</u>

Explanation:

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Answer:

1.5 m

Explanation:

H = actual height of the superhero = ?

H₀ = height of the superhero as observed = 1.73 m

v = speed of the superhero = 0.50 c

Using the equation

H = H_{o} \sqrt{1 - \left ( \frac{v}{c} \right )^{2}}

Inserting the values

H = 1.73 \sqrt{1 - \left ( \frac{0.50 c}{c} \right )^{2}}

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A 1500 kg elevator, suspended by a single cable with tension 16.0 kN, is measured to be moving upward at 1.2 m/s. Air resistance
kirill115 [55]

Tension in the Cable is 0.87 m/s6^2, Elevator's speed after it has moved 10m is 1.6*10^5 N, Work done by gravity is  1.47 * 10^3 N, Elevator Kinetic Energy is 13897.5J and Elevator Speed after rising to 10m is 4.312 m/s.

Tension is a pulling force that operates in one dimension along the cables' axes in the opposite direction from the direction of the applied force. The combined weight of the elevator box and the passenger riding inside it, in the case of an elevator, provides the pulling force in the cables is called Tension.

A moving object or particle's kinetic energy, which depends on both mass and speed, is one of its characteristics. The type of motion can be vibration, translation, rotation around an axis, or any combination of these. Kinetic energy is a type of energy that an item or particle possesses as a result of motion.

We know that,

Tension in the Cable

T = m(g+a)  = g+a = T/m = 16 * 103 / 1500 = 10.67 m/s2

a = 10.67 - 9.8 = 0.87 m/s6^2

Elevator's speed after it has moved 10m.

U^2 = u^2 +2as

= 1.22 +2*0.87*10

=1.6*10^5 N

Work done by gravity  = mg * 10 = 14700 * 10 = 1.47 * 10^3 N

Elevator Kinetic Energy = 1/2 mv^2 = 1/2*1500*18.53 = 13897.5J

Elevator Speed after rising to 10m ,

U^2 = u^2 +2as =  1.2 +2*0.87*10 = 18.6

U =(18.6)^1/2=4.312 m/s

Learn more about Kinetic Energy here

brainly.com/question/26472013

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6 0
1 year ago
Interchangeably means​
ryzh [129]

Answer:

Interchangeable is something that can be used in the same manner as something else without any important differences.

or in a more simple way

something that can be exchange

For example when two sweaters look almost the same and you could easily wear either one with a particular skirt, this is an example of when the sweaters can be worn interchangeably.

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3 years ago
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Answer:

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Explanation:

The train accelerate from the rest so u = 0 m/sec

Final speed that is v = 80 m/sec

Time t = 30 sec

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We know the equation of motion S=ut+\frac{1}{2}at^2 where s is distance a is acceleration and u is initial velocity

Using this equation for first plane 1200=0\times 30+\frac{1}{2}a30^2

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As the acceleration is same for both the plane so a for second plane will be 2.67 \frac{m}{sec^2}

The another equation of motion is v^2=u^2+2as using this equation for second plane 40^2=0+2\times 2.67\times s

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Mamont248 [21]

Answer:

Explanation:

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