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julsineya [31]
2 years ago
11

PLEASE HELP ME!!!!! You draw an arrow from left to right on a piece of paper and place the paper well behind a glass of water. Y

ou observe that the direction of the arrow appears reversed behind the water glass!
What conclusions can you draw from this experiment?


(1 point)


The arrow appears reversed because light is bent as it enters the water, and again as it exits. The two light paths cross, making the direction of the arrow appear crossed.

The arrow appears reversed because light is bent as it enters the water, and again as it exits. The two light paths cross, making the direction of the arrow appear crossed.


The arrow appears reversed because light is reflected by the glass of water. Light is reflected so much that the arrow appears to face the other direction.

The arrow appears reversed because light is reflected by the glass of water. Light is reflected so much that the arrow appears to face the other direction.


It is not possible for the arrow to appear reversed behind a glass of water. The most likely explanation is that a mistake was made during the experiment.

It is not possible for the arrow to appear reversed behind a glass of water. The most likely explanation is that a mistake was made during the experiment.


The arrow appears reversed because light is split as it enters the water, and combines again as it exits the water. When the light re-combines, the arrow appears to be flipped.

Physics
1 answer:
julia-pushkina [17]2 years ago
7 0

Answer:

I think it is the first one: <u>The arrow appears reversed because light is bent as it enters the water, and again as it exits. The two light paths cross, making the direction of the arrow appear crossed.</u>

Explanation:

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Explanation:

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3 years ago
Your high-fidelity amplifier has one output for a speaker of resistance 8 Ω. How can you arrange two 8-Ω speakers, one 4-Ω speak
ANTONII [103]

Answer:

(a) 8Ω (b)  Ratio = Parra/P8 ohm = 1

Explanation:

Solution

Recall that,

An high-fidelity amplifier has one output for a speaker of resistance of = 8 Ω

Now,

(a) How can  two 8-Ω speakers be  arranged, when one =  4-Ω speaker, and one =12-Ω speaker

The Upper arm is : 8 ohm, 8 ohm

The Lower arm is : 12 ohm, 4 ohm

The Requirement is  = (16 x 16)/(16 + 16) = 8 ohm

(b) compare  your arrangement  power output of with the power output of a single 8-Ω speaker

The Ratio = Parra/P8 ohm = 1

8 0
3 years ago
A parallel plate capacitor with air between the plates has a potential difference of 71.0 V. Determine the potential difference
Gwar [14]

Answer:

15.8 V

Explanation:

The relationship between capacitance and potential difference across a capacitor is:

q=CV

where

q is the charge stored on the capacitor

C is the capacitance

V is the potential difference

Here we call C and V the initial capacitance and potential difference across the capacitor, so that the initial charge stored is q.

Later, a dielectric material is inserted between the two plates, so the capacitance changes according to

C'=kC

where k is the dielectric constant of the material. As a result, the potential difference will change (V'). Since the charge stored by the capacitor remains constant,

q=C'V'

So we can combine the two equations:

CV=CV'\\CV=(kC)V'\\V'=\frac{V}{k}

and since we have

V = 71.0 V

k = 4.50

We find the new potential difference:

V'=\frac{71.0}{4.50}=15.8 V

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3 years ago
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kumpel [21]

Answer:

I'm Pretty sure the answer your looking for is C

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3 years ago
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