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alekssr [168]
2 years ago
12

How did the believers show their fellowship with one another?​

Chemistry
1 answer:
k0ka [10]2 years ago
8 0

Answer:

I think you may have chosen the wrong subject for your question, besides where is the context to this?

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. Nhiệt độ ban đầu của 344 g một mẫu sắt là 18,2oC. Nếu mẫu sắt này hấp thụ 2,25 kJ nhiệt lượng thì nhiệt độ cuối của mẫu sắt nà
Mrrafil [7]

Answer:

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8 0
3 years ago
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The electrons in an insulator are tightly bound to their atoms.
Murrr4er [49]
If its a true or false statement . the answer is true 
4 0
3 years ago
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Saturated hydrocarbons are generally unreactive except in the presence of _____.
Citrus2011 [14]
Hello!

Saturated hydrocarbons are generally unreactive except in the presence of high temperatures and oxygen.

Saturated hydrocarbons are called Alkanes. These compounds are generally unreactive, but when exposed to high temperatures and oxygen they react in a combustion reaction to produce Carbon Dioxide and Water. This reaction is very violent and spontaneous and explosions of household gas cylinders occur because of the spontaneity of this reaction.

Have a nice day!
6 0
3 years ago
NH4Cl and Na2SO4<br> Balanced Equation<br> Total Ionic Equation<br> Net Ionic Equation
Veseljchak [2.6K]

Answer:

No Reaction => does not form a Driving Force Compound

Explanation:

3 0
3 years ago
If the formation of NaCl proceeds according to the following equation and change in enthalpy, what is the reaction and change in
Sergio039 [100]

Answer:

  • <em>2NaCl → 2Na + Cl₂, ΔH = 822 kJ </em>

Explanation:

The chemical <em>equation</em> for the <em>formation of NaCl</em> is:

  • Na + (1/2) Cl₂ → NaCl , ΔH = - 411 kJ

That equation means that 1 mole of NaCl is formed by the reaction of 1 mole of Na and 1/2 mole of Cl₂, with a release of energy of 411 kJ.

The <em>decomposition</em> of <em>NaCl</em> is the inverse of the <em>formation</em> reaction; thus, you swift products and reactants and inverse the sign of the <em>change in enthalpy:</em>

  • NaCl → Na + 1/2 Cl₂, ΔH = 411 kJ

Since you want the decomposition of 2 moles you multiply the equation and the ΔH by 2:

  • 2NaCl → 2Na + Cl₂, ΔH = 822 kJ ← answer

3 0
3 years ago
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