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2 years ago

How did the believers show their fellowship with one another?

Chemistry

1 answer:

k0ka [10]2 years ago

8 0

Answer:

I think you may have chosen the wrong subject for your question, besides where is the context to this?

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As Matter Changes States of matter does chemical composition stay the same or not

geniusboy [140]

Whether water is frozen, in a gaseous state, or is a liquid, it is still H2O. So the chemical composition does stay the same.

6 0

4 years ago

How many hydrogen atoms are found in the hydrate (NH4)3PO4.5H2O?

igomit [66]

Answer:

Explanation:

3x4+ 5x2

3 0

3 years ago

Indicate the peptides that would result from cleavage by the indicated reagent: a. Gly-Lys-Leu-Ala-Cys-Arg-Ala-Phe by trypsin b.

Ilia_Sergeevich [38]

Answer:

a. Gly-Lys + Leu-Ala-Cys-Arg + Ala-Phe

b. Glu-Ala-Phe + Gly-Ala-Tyr

Explanation:

In this case, we have to remember which peptidic bonds can break each protease:

-) Trypsin

It breaks selectively the peptidic bond in the carbonyl group of lysine or arginine.

-) Chymotrypsin

It breaks selectively the peptidic bond in the carbonyl group of phenylalanine, tryptophan, or tyrosine.

With this in mind in "peptide a", the peptidic bonds that would be broken are the ones in the "Lis" and "Arg" (See figure 1).

In "peptide b", the peptidic bond that would be broken is the one in the "Phe" (See figure 2). The second amino acid that can be broken is tyrosine, but this amino acid is placed in the C terminal spot, therefore will not be involved in the hydrolysis.

3 0

3 years ago

A student measures the mass of a 10m^3 block of gold to be 500 kg what is the density of the gold

Anuta_ua [19.1K]

Answer:

d = 50 kg/m³

Explanation:

density = $\frac{mass}{volume}$

mass = 500 kg

volume = 10m³

$\frac{500}{10}$ = 50

d = 50 kg/m³

8 0

3 years ago

zn (s) 2 hcl (aq) -----> zncl2 (aq) h2(g) if 520 ml of h2 is collected over water at 28oc and the atmospheric pressure is 1.0

nadya68 [22]

The Zn that is 1.33 g is used at the start of the reaction where f is 520 ml and h2 collected over water is 28oc and the atmospheric pressure is 1.0 atm.

Given If 520 ml of H2 is gathered over Wate at 28 diploma Celsius and the atmospheric strain is 1 ATM if vapour strain of wate at 28 diploma celsius is 28.three mmhg then the quantity of zn in grams taken at begin of the response is.

We recognise that

h * 2 = PT - P * h * 20 = 1atm - 0.037atm

= 0.963 atm

1 * h * 2 = Ph * 2V / R * T

= 0.963 atm x 0.520 L / 0.0821 L atm/

molK * 301

= 0.02 mol h2

= 0.02molZn

So 0.02 mol Zn x 65.39 g/mol

= 1.33 g Zn

How did the believers show their fellowship with one another?​

How did the believers show their fellowship with one another?