Answer:
Your answer would be D.) Convection. I hope this helps you! :)
Moving down in a group, the electronegativity decreases due to an increase in the distance between the nucleus and the valence electron shell, thereby decreasing the attraction, making the atom have less of an attraction for electrons or protons.
Answer : The mass of the water in two significant figures is, ![3.0\times 10^1g](https://tex.z-dn.net/?f=3.0%5Ctimes%2010%5E1g)
Explanation :
In this case the heat given by the hot body is equal to the heat taken by the cold body.
![q_1=-q_2](https://tex.z-dn.net/?f=q_1%3D-q_2)
![m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_f-T_1%29%3D-m_2%5Ctimes%20c_2%5Ctimes%20%28T_f-T_2%29)
where,
= specific heat of iron metal = ![0.45J/g^oC](https://tex.z-dn.net/?f=0.45J%2Fg%5EoC)
= specific heat of water = ![4.18J/g^oC](https://tex.z-dn.net/?f=4.18J%2Fg%5EoC)
= mass of iron metal = 32.3 g
= mass of water = ?
= final temperature of mixture = ![59.2^oC](https://tex.z-dn.net/?f=59.2%5EoC)
= initial temperature of iron metal = ![21.9^oC](https://tex.z-dn.net/?f=21.9%5EoC)
= initial temperature of water = ![63.5^oC](https://tex.z-dn.net/?f=63.5%5EoC)
Now put all the given values in the above formula, we get
![32.3g\times 0.45J/g^oC\times (59.2-21.9)^oC=-m_2\times 4.18J/g^oC\times (59.2-63.5)^oC](https://tex.z-dn.net/?f=32.3g%5Ctimes%200.45J%2Fg%5EoC%5Ctimes%20%2859.2-21.9%29%5EoC%3D-m_2%5Ctimes%204.18J%2Fg%5EoC%5Ctimes%20%2859.2-63.5%29%5EoC)
![m_2=30.16g\approx 3.0\times 10^1g](https://tex.z-dn.net/?f=m_2%3D30.16g%5Capprox%203.0%5Ctimes%2010%5E1g)
Therefore, the mass of the water in two significant figures is, ![3.0\times 10^1g](https://tex.z-dn.net/?f=3.0%5Ctimes%2010%5E1g)
Answer:
What is the reaction quotient, Q, for this system when [N2] = 2.00 M, [H2] = 2.00 M, and [NH3] = 1.00 M at 472°C?
A. 0.0625
How does Q compare to Keq?
B. Q < Keq
Explanation: