199.5 g of sucrose is needed to make 665 ml of 30 % weight by volume percent solution.
<h3>What is percent solution?</h3>
Percent solution is defined as a convenient way to record concentration of solution.It is a expression which relates solute to solvent as,mass of solute/mass of solution ×100.There are two types of percentage solutions percent weight by volume and percent volume by volume .Advantages of using percent solutions is that molecular weight of compound is not required.
This example is percent weight by volume where mass of solute is calculated as,%(w/v)= mass of solute/mass of solution×100
substitution of values gives,30×665/100=199.5 g
Thus ,199.5 g of sucrose is required to make 665 ml of 30 % sucrose solution.
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Sulfer and fluorine but you need special equipment to get it
Answer:
A) , ,
A = 1.5×, A = 1.9×, A=1.5×
B) 4.469
Explanation:
From Arrhenius equation
where; K = Rate of constant
A = Pre exponetial factor
= Activation Energy
R = Universal constant
T = Temperature in Kelvin
Given parameters:
taking logarithm on both sides of the equation we have;
since we have the rate of two different temperature the equation can be derived as:
= 19846.04×7.544× = 1.497
= = 4.469
A gas with a vapor density greater than that of air, would be most effectively displaced out off a vessel by ventilation.
The two following principles determine the type of ventilation: Considering the impact of the contaminant's vapour density and either positive or negative pressure is applied.
Consider a vertical tank that is filled with methane gas. Methane would leak out if we opened the top hatch since its vapour density is far lower than that of air. A second opening could be built at the bottom to greatly increase the process' efficiency.
A faster atmospheric turnover would follow from air being pulled in via the bottom while the methane was vented out the top. The rate of natural ventilation will increase with the difference in vapour density. Numerous gases that require ventilation are either present in fairly low concentrations or have vapor densities close to one.
To find the balanced reaction, you have to predict the products and write the equation first.
This will be a single replacement reaction because aluminum is an element and copper nitrate is a compound.
The reaction will be:
Al + Cu(NO3)2 -> Cu + Al(NO3)3
Now, we can balance it:
2 Al + 3 Cu(NO3)2 -> 3 Cu + 2 Al(NO3)3