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Anastaziya [24]
3 years ago
8

What is the half life of this element? A. 80 days B. 40 days C. 5 days D. 10 days

Chemistry
1 answer:
masha68 [24]3 years ago
4 0

Answer:

c. 5days

Explanation:

there is no question but if it's a graph

the answer is 5days

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Evgen [1.6K]

<em>Answer:</em>

4) the one that is reduced, which is the oxidizing agent

<em>Explanation:</em>

<em>An oxidizing agent is one that causes oxidation by gaining electrons from another atom/molecule. </em>

6 0
3 years ago
Which property would cesium most likely have?
Romashka-Z-Leto [24]
The answer is a because its not low ductile or gasst

8 0
3 years ago
Read 2 more answers
A sample of an unknown metal has a mass of 58.932g. it has been heated to 101.00 degrees C, then dropped quickly into 45.20 mL o
yaroslaw [1]
<h3>Answer:</h3>

0.111 J/g°C

<h3>Explanation:</h3>

We are given;

  • Mass of the unknown metal sample as 58.932 g
  • Initial temperature of the metal sample as 101°C
  • Final temperature of metal is 23.68 °C
  • Volume of pure water = 45.2 mL

But, density of pure water = 1 g/mL

  • Therefore; mass of pure water is 45.2 g
  • Initial temperature of water = 21°C
  • Final temperature of water is 23.68 °C
  • Specific heat capacity of water = 4.184 J/g°C

We are required to determine the specific heat of the metal;

<h3>Step 1: Calculate the amount of heat gained by pure water</h3>

Q = m × c × ΔT

For water, ΔT = 23.68 °C - 21° C

                       = 2.68 °C

Thus;

Q = 45.2 g × 4.184 J/g°C × 2.68°C

    = 506.833 Joules

<h3>Step 2: Heat released by the unknown metal sample</h3>

We know that, Q =  m × c × ΔT

For the unknown metal, ΔT = 101° C - 23.68 °C

                                              = 77.32°C

Assuming the specific heat capacity of the unknown metal is c

Then;

Q = 58.932 g × c × 77.32°C

   = 4556.62c Joules

<h3>Step 3: Calculate the specific heat capacity of the unknown metal sample</h3>
  • We know that, the heat released by the unknown metal sample is equal to the heat gained by the water.
  • Therefore;

4556.62c Joules = 506.833 Joules

c = 506.833 ÷4556.62

  = 0.111 J/g°C

Thus, the specific heat capacity of the unknown metal is 0.111 J/g°C

8 0
3 years ago
What is the percent of copper in CuS?
bonufazy [111]

Answer:

Element Symbol Mass Percent

Cuprum Cu 66.464%

Sulfur S 33.537%

Explanation:

I got this out of my module, sorry if it's wrong but i am pretty sure 97% this is correct!

7 0
2 years ago
What is the density of an 800 gram object that occupies 200 cm 3 ?
vova2212 [387]
Density = mass/volume = 800/200 =4 g/cm^3
8 0
2 years ago
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