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charle [14.2K]
3 years ago
9

How long does it take a 750-w coffeepot to bring to a boil 0.75 l of water initially at 11°c? assume that the part of the pot wh

ich is heated with the water is made of 280 g of aluminum, and that no water boils away?
Physics
1 answer:
Evgen [1.6K]3 years ago
4 0
Just add all of them up and there is your answer I just added it but  I want u to work it out to..


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A car is making a 40 mi trip. It travels the first half of the total distance 20.0 mi at 18.00 mph and the last half of the tota
sukhopar [10]

Answer: The average speed is 27,24 mph (exactly 1008/37 mph)

Explanation:

This is solved using a three rule: We know the speeds and the distances, what we can obtain from it is the time used. It is done like this:

1h--->18mi

X ---->20 mi, then X=20mi*1h/18mi= 10/9 h=1,111 h

1h--->56mi

X ---->20 mi, then X=20mi*1h/56mi= 5/14 h=0,35714 h

Then the average speed is calculated by taking into account that it was traveled 40mi and the time used was 185/126 h=1,468 h and since speed is distance over time we get the answer. Average speed= 40mi/(185/126 h)=1008/37 mph=27,24 mph.

5 0
3 years ago
When an electric current flows through a long conductor, each free electron moves
ki77a [65]
A. through a relatively short distance.

The speed is actually called the drift speed of the electron.
7 0
3 years ago
Who has the best answer for this
ioda

Answer:

electricity because it has more percentage nd energy

Explanation:

mark me brainliest pl

6 0
1 year ago
Convert the following measurements as indicated, show work. write the answer in scientific notation.
mojhsa [17]

Answer:

A. 0.95 m

B. 1,100 ml

C. 17 km

D. 500,000 g

Explanation:

A. 95/100

B. 1.1 x 1,000

C. 17,000/1,000

D. 500 x 1,000

4 0
2 years ago
Read 2 more answers
Use Hooke's Law to determine the variable force in the spring problem. A force of 450 newtons stretches a spring 30 centimeters.
ladessa [460]

Answer:

Work Done = 67.5 J

Explanation:

First we find the value of spring constant (k) using Hooke's Law. Hooke's is formulated as:

F = kx

where,

F = Force Applied = 450 N

k = Spring Constant = ?

x = Stretched Length = 30 cm = 0.3 m

Therefore,

450 N = k(0.3 m)

k = 450 N/0.3 m

k = 1500 N/m

Now, the formula for the work done in stretching the spring is given as:

W = (1/2)kx²

Where,

W = Work done = ?

k = 1500 N/m

x = 70 cm - 40 cm = 0.3 m

Therefore,

W = (1/2)(1500 N/m)(0.3 m)²

<u>W = 67.5 J</u>

3 0
2 years ago
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