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Lyrx [107]
3 years ago
7

While driving on a highway, your HMMWV starts to pull to one side. You stop and check your tires – one tire is going flat. There

is no spare, but the affected tire has a runflat device installed, and you are only 5 miles from the motor pool. What is your maximum allowable speed when driving with one flat tire?
Physics
1 answer:
MrRissso [65]3 years ago
3 0

Answer:

30 miles people hour (mph)

Explanation:

The maximum speed for one flat tyre is 30mph, for both tyres it is 20 mph and for two tyres on the same side it is 30mph. When a tyre is punctured driving at high speed should be avoided and not too long distance should be covered to avoid further accident and for the safety of other vehicles. Speed limit and distance for flat tires should be strictly followed.

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Unpolarized light with intensity S is incident on a series of polarizing sheets. The first sheet has its transmission axis orien
jeka94

Answer:

Explanation:

Given

Initial Intensity of light is S

when an un-polarized light is Passed through a Polarizer then its intensity reduced to half.

When it is passed through a second Polarizer with its transmission axis \theat =45^{\circ}

S_1=S_0\cos ^2\theta

here S_0=\frac{S}{2}

S_1=\frac{S}{2}\times \frac{1}{(\sqrt{2})^2}

S_1=\frac{S}{4}

When it is passed through third Polarizer with its axis 90^{\circ} to first but \theta =45^{\circ} to second thus S_2

S_2=S_0\cos ^2\theta

S_2=\frac{S}{4}\times \frac{1}{2}

S_2=\frac{S}{8}

When middle sheet is absent then Final Intensity will be zero                    

3 0
3 years ago
Some compounds, like carbon dioxide, are gaseous at room temperature, while others are solid at room temperature. Why is this?
Vesnalui [34]
The answer of a & b are force of cohesion and force of adhesion
Of rest two answers I don't know 
8 0
3 years ago
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A sphere of mass 40kg is attaracted by a second sphere of mass 15 kg when their centers are 20 cm apart with a force of 0.1mg-wt
ser-zykov [4K]
<span>gravitational force = 0.1 mg-wt. = 0.1 * 10^-6 * 9.8 N = Gm1m2/r^2
 m1 = 40 kg m2 =15 kg and r = 0.2 m
 Put in and find G</span>
3 0
3 years ago
In a very busy off-campus eatery one chef sends a 201 g broccoli-tomato-pickle-onion-mushroom pizza sliding down the counter fro
Murrr4er [49]

Answer:

The correct answer is:

(A) to the left

(B) at speed -0.8725 m/s

Explanation:

The given values are:

Plate 1:

Mass,

m₁ = 201 g

Velocity,

v₁ = +1.79 m/s

Plate 2:

Mass,

m₁ = 335 g

Velocity,

v₁ = -2.47 m/s

According to the conservation of momentum, we get

⇒  m_1v_1+m_2v_2=(m_1+m_2)v

then,

⇒  v=\frac{m_1v_1+m_2v_2}{m_1+m_2}

On substituting the values, we get

⇒     =\frac{201\times 1.79+335\times (-2.47)}{201+335}

⇒     =\frac{359.79-827.45}{536}

⇒     =\frac{-467.66}{536}

⇒     =-0.8725 (to the left)

3 0
3 years ago
Which area on the line has both some kinetic energy and some gravitational energy?
Yakvenalex [24]
I believe it is either A or B
4 0
3 years ago
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