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SCORPION-xisa [38]
3 years ago
12

An object is moving at a constant velocity of 10 m/s for 5 seconds. What is

Physics
1 answer:
german3 years ago
3 0

initial velocity (u)=0m/s

final velocity (v)=10m/s

time( t)=5s

acceleration (a)=v-u÷t

acceleration (a)=10-0÷5

acceleration (a)=10÷5

acceleration (a)=2

therefore acceleration (a)=2m/s

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Answer:

a

e(k) =  \frac{2a}{c}  *  sin (\frac{k*a}{2} )

b

G_{v} =  \frac{d e(k ) }{dk }  =  \frac{a^2}{c}  *  cos (\frac{k* a}{2} )

Explanation:

From the question we are told that

    The  velocity  of transverse waves in a crystal of atomic separation is  

                  b_y  = c \frac{sin (\frac{k*a}{2} )}{\frac{k*a}{2} }

Generally the dispersion relation is mathematically represented as

            e(k) =  b_y  *  k

=>    e(k) = c  \frac{sin(\frac{k*a}{2} ) }{ \frac{k*a}{2} }  *  k

=>    e(k) =   c *  \frac{sin (\frac{k_a}{2} )}{ \frac{a}{2} }

=>    e(k) =  \frac{2a}{c}  *  sin (\frac{k*a}{2} )

Generally the group velocity is mathematically represented as

          G_{v} =  \frac{d e(k ) }{dk }  =  \frac{a^2}{c}  *  cos (\frac{k* a}{2} )

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You are making cookies that call for 3 tablespoons of molasses, but you are having trouble measuring out the thick, syrupy liqui
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<h3>Amplitude of sound wave</h3>

The amplitude of a sound wave is the maximum vertical displacement of the sound wave.

The sound mixer will need to increase the amplitude of the sound wave produced by the singer.

The increase in the amplitude of the sound wave produced by the lower tune singer will result in increased loudness of the sound.

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