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kvasek [131]
3 years ago
10

Calcium carbonate reacts with hydrochloric acid to form calcium chloride, carbon dioxide, and water. What mass of hydrochloric a

cid will be needed to produce 5.00 x 10 3 kg of calcium chloride?
Chemistry
1 answer:
sergij07 [2.7K]3 years ago
7 0

Answer:

3284.3 kg is the mass of HCl needed to produce 5000 kg of CaCl₂

Explanation:

This is the reaction:

CaCO₃ + 2HCl →  CaCl₂  +  CO₂  +  H₂O

Let's convert the mass of the product to moles (mass (g) / molar mas)

Firstly we must convert kg to g

1 kg = 1000 g

5×10³ kg . 1000 g / 1 kg = 5×10⁶ g

5×10⁶ g / 110.98 g/mol = 45053.1 moles

Ratio is 1:2 So, let's make a rule of three:

1 mol of CaCl₂ was produced by the use of 2 moles of HCl

So 45053.1 moles of salt, were produced by, the double of moles

45053.1 mol . 2 → 90106.2 moles

Let's convert the moles, to mass (mol . molar mass)

90106.2 mol . 36.45 g/mol = 3284375 g → 3284.3 kg

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How many moles are contained in 2.0 L of N2 at standard temperature and pressure.
GuDViN [60]

0.091 moles are contained in 2.0 L of N2 at standard temperature and pressure.

Explanation:

Data given:

volume of the nitrogen gas = 2 litres

Standard temperature = 273 K

Standard pressure = 1 atm

number of moles =?

R (gas constant) = 0.08201 L atm/mole K

Assuming nitrogen to be an ideal gas at STP, we will use Ideal Gas law

PV = nRT

rearranging the  equation to calculate number of moles:

PV = nRT

n = \frac{PV}{RT}

putting the values in the equation:

n = \frac{1X2}{0.08201 X 273}

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What is the theoretical yield of NaBr
dolphi86 [110]

The theoretical yield of NaBr given that 2.36 moles of FeBr₃ reacts is 7.08 moles

<h3>Balanced equation </h3>

2FeBr₃ + 3Na₂S → Fе₂S₃ + 6NaBr

From the balanced equation above,

2 moles FeBr₃ reacted to produce 6 moles of NaBr

<h3>How to determine the theoretical yield of NaBr</h3>

From the balanced equation above,

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Therefore,

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Thus, the theoretical yield of NaBr is 7.08 moles

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brainly.com/question/14735801

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