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alex41 [277]
3 years ago
6

Complete the balanced molecular chemical equation for the reaction below. If no reaction occurs, write NR after the reaction arr

ow. Pb ( N O ₃ ) ₂ (aq) + K I (aq) → ☐⁴⁻ ☐³⁻ ☐²⁻ ☐⁻ ☐⁺ ☐²⁺ ☐³⁺ ☐⁴⁺ 1 2 3 4 5 6 7 8 9 0 ☐₁ ☐₂ ☐₃ ☐₄ ☐₅ ☐₆ ☐₇ ☐₈ ☐₉ ☐₀ + ( ) → ⇌ (s) (l) (g) (aq) NR Pb I N O K Reset
Chemistry
1 answer:
Nostrana [21]3 years ago
8 0

Answer: Pb(NO_3)_2(aq)+2KI(aq)\rightarrow PbI_2(s)+2KNO_3(aq)

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

The double displacement reaction in which one of the product is formed as a solid is called as precipitation reaction.

The balanced molecular equation is:

Pb(NO_3)_2(aq)+2KI(aq)\rightarrow PbI_2(s)+2KNO_3(aq)

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What are examples of evaporation?
jekas [21]

Answer:

Boiling water

Explanation:

The water evaporates from the pot

6 0
3 years ago
Read 2 more answers
A lab technician needs a 40% solution of a certain chemical for an experiment, but the lab that she works in only has a 20% solu
Snezhnost [94]

To determine the volume of both concentration of the solution to make another concentration of solution, we need to set up two equations since we have two unknowns. <span>

For the first equation, we do a mass balance:

mass of 50% solution + mass of 20% solution = mass of 40% solution
M1 + M2 = M3

For the second equation, we do a component balance,</span>

<span>
M1(50%) + M2(20%) = M3(40%)
.50M1 + .20M2 = .40M3

To determine the ratio, we assume we have to make a 100 g of the 40% solution. So, the equation would change to</span>

<span>
</span>

<span>M1 + M2 = 100</span>

.50M1 + .20M2 = (100)(.40) = 40


Solving for M1 and M2,

M1 = 66.67 g

M2 = 33.33 g


So, the ratio of the 20% and the 50% would be approximately 33.33/66.67 = 0.5.

8 0
3 years ago
A rigid cylinder with a movable piston contains a sample of gas. At 300. K, this sample has a pressure of 240. kilopascals and a
maxonik [38]

Answer:

52.5 mL

Explanation:

6 0
4 years ago
twelve grams of sodium chloride wwere dissolved in 52 ml (52g) of distilled water, calculate the % sodium chloride in the soluti
Delicious77 [7]

Answer:

The mass of sodium chloride in the mixture is 18.75%

Explanation:

Here, we want to calculate the percentage of sodium chloride in the mixture.

The total mass of the mixture is 52 g + 12 g = 64 g

So the percentage mass of sodium chloride will be;

mass of sodium chloride/ Total mass * 100%

That will be: 12/64 * 100 = 18.75%

8 0
3 years ago
What volume of a 0.317 M HBR solution is required to neutralize 18.8mL of a 0.129 M KOH solution?
lozanna [386]

Answer:

\large \boxed{\text{7.65 mL}}

Explanation:

1. Balanced chemical equation.

\rm HBr + KOH \longrightarrow KBr + H_{2}O

2. Moles of NaOH

\text{Moles of NaOH} =\text{ 18.8 mL NaOH} \times \dfrac{\text{0.129 mmol NaOH }}{\text{1 mL NaOH }} =  \text{2.425 mmol NaOH }

3. Moles of HBr

The molar ratio is 1 mmol HBr:1 mmol NaOH

\text{Moles of HBr}=  \text{2.425 mmol NaOH} \times \dfrac{\text{1 mmol HBr}}{\text{1 mmol NaOH}} =\text{2.425 mmol HBr}

4. Volume of HBr

V = \text{2.425 mmol HBr}\times \dfrac{\text{1mL HBr}}{\text{0.317 mmol HBr}} =   \textbf{7.65 mL HBr}\\\\\text{The reaction requires $\large \boxed{\textbf{7.65 mL HBr}}$}

5 0
3 years ago
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