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spayn [35]
3 years ago
14

Two cars move down a hill at a constant velocity. Car c is much larger than car d. The car that has a greater momentum is:

Physics
2 answers:
babunello [35]3 years ago
7 0

Answer:

C

Explanation:

When an object has a greater mass than the drag force pushing it back then it    is moving forward therefore making car C faster than car D. If car D was much smaller it wouldn't have enough mass to push past the drag force.

BlackZzzverrR [31]3 years ago
4 0
The answer would be c
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What is the momentum of a 0.1-kg mass moving with a speed of 5 m/s
Andrej [43]
This question is wrong because in momontum we will write acceleration instead of speed.     suppose acceleration is 5m/s2 then 
 P= ma 
                then put values
   
4 0
3 years ago
Inertia is a measure of
saw5 [17]

Answer:

b.. a difficulty of changing an object's motion, that's my ✨ g u e s s ✨

7 0
2 years ago
If a longitudinal wave passes a specific point seven times per second, and the distance between wave rarefaction points is 2 met
zavuch27 [327]

Answer: 14 m/s

Explanation:

The speed S of a sound wave is given by the following equation:

S=\lambda f

Where:

\lambda=2 m is the wavelength of the sound wave

f=7 times/s=7 Hz

S=(2 m)(7 Hz)

Hence:

S=14 m/s

4 0
3 years ago
Show all work.
lys-0071 [83]

The new gravitation force at the new location is 40 N

Explanation:

The weight of the astronaut is given by the equation

F=mg (1)

where

m is the mass of the astronaut

g is the acceleration of gravity

The acceleration of gravity at a certain distance r from the centre of the Earth is given by

g=\frac{GM}{r^2}

where G is the gravitational constant and M is the Earth's mass. So we can rewrite eq.(1) as

F=\frac{GMm}{r^2}

When the astronaut is on the Earth's surface, r=R (where R is the Earth's radius), so his weight is

F=\frac{GMm}{R^2}=640 N

Later, he moves to another location where his distance from the Earth's surface is 3 times the previous distance, so the new distance from the Earth's centre is

r'=3R+R=4R

Therefore, the new weight is

F'=\frac{GMm}{(4R)^2}=\frac{1}{16}\frac{GMm}{R^2}=\frac{F}{16}

Which means that his weight has decreased by a factor 16: therefore, the new weight is

F'=\frac{640}{16}=40 N

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

3 0
3 years ago
A tank with a flat bottom is filled with water to a height of 4 meters. What is the pressure at any point at the bottom of the t
Mariulka [41]

<u>Answer</u>

C.39.2 kPa


<u>Explanation</u>

The pressure in liquids depend on the depth or what we call the liquid column(h), the density of the liquid(σ) and the the acceleration due to gravity(g).

h = 4.00 m

σ = 1000 Kg/m³

g = 9.8m/s²


Pressure Is given by;

P = σgh

= 1000 × 9.8 × 4

= 39200 Pa

=39.2 KPa

8 0
3 years ago
Read 2 more answers
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