Assume that an ingot of copper has a mass of 9.1 kg or 9100 g.
The cross-sectional area of the copper wire with diameter of 6.5 mm (or 0.65 cm) is
A = (π/4)*(0.65 cm)² = 0.3318 cm²
The density of copper is given as 8.94 g/cm³.
If the length of copper wire is L cm, then
(0.3318 cm²)*(L cm)*(8.94 g/cm³) = 9100 g
L = 9100/(0.3318*8.94) = 3.0678 x 10³ cm
Note that
1 cm = 1/2.54 in = 1/2.54 in = 0.3937 in
= 0.3937/12 = 0.03281 ft
Therefore
L = (3.0678 x 10³ cm)*(0.03281 ft/cm) = 100.65 ft
Answer: 100.65 ft
Answer:
Explanation:
Angular momentum ( L ) = moment of inertia x angular velocity ( I X ω )
Moment of inertia of two 480 g masses about axle = 2 x mr² = 2 x 480 x10⁻³ x( 24 x 10 ⁻ 2 )² = 0. 552960 kg m².
Angular velocity = 5 rad / s.
Angular momentum = 0.552960 x 5 = 2.765 kg m2.
The direction of angular momentum will be along axle.So vector angular
momentum makes zero degree with axle.
Answer:
1.16kg is the answer. Hope this helped
Explanation:
Answer:
Explanation:
the same amount of time in both halves of the circle
An inner transition metal (ITM) is one of a group of chemical elements on the periodic table. They are normally shown in two rows below all the other elements. They include elements 57-71 (lanthanides) and 89-103 (actinides).