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Rasek [7]
4 years ago
11

You arrive in my class 45 seconds after leaving math which is 90 meters away. How fast did you travel?

Physics
1 answer:
pashok25 [27]4 years ago
4 0

Answer:

2m/s

Explanation:

speed = distance÷time

speed =90÷45=2m/s

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The wavelength of red light is 7 x 10^-7 meter. Express this value in nanometers
3241004551 [841]

  • The wavelength of the red light in "nanometer" is 7× 10^{2}

  • Wavelength is given as : 7×10^{-7} meter

  • 1 nanometer = (10^{-9} meter)

  • Let X= value of the wavelength in nanometer.

1 nanometer  = 10^{-9} meter

X nanometer = 7× 10^{-7}  meter

  • <em>If we Cross multiply</em>

X nanometer = (\frac{     7* 10^{-7} }{  10^{-9} })

X= 7×10^{2} nanometer

Therefore, the wavelength in "nanometer" is 7×10^{2}

Learn more at :brainly.com/question/12924624?referrer=searchResults

6 0
3 years ago
Science Help Please?? It is believed that solar nebular material came from which of the following:
kolbaska11 [484]
B would be the answer to this
7 0
3 years ago
Read 2 more answers
Energy Conservation With Conservative Forces: If a spring-operated gun can shoot a pellet to a maximum height of 100 m on Earth,
crimeas [40]

Answer:

h' = 603.08 m

Explanation:

First, we will calculate the initial velocity of the pellet on the surface of Earth by using third equation of motion:

2gh = Vf² - Vi²

where,

g = acceleration due to gravity on the surface of earth = - 9.8 m/s² (negative sign due to upward motion)

h = height of pellet = 100 m

Vf = final velocity of pellet = 0 m/s (since, pellet will momentarily stop at highest point)

Vi = Initial Velocity of Pellet = ?

Therefore,

(2)(-9.8 m/s²)(100 m) = (0 m/s)² - Vi²

Vi = √(1960 m²/s²)

Vi = 44.27 m/s

Now, we use this equation at the surface of moon with same initial velocity:

2g'h' = Vf² - Vi²

where,

g' = acceleration due to gravity on the surface of moon = 1.625 m/s²

h' = maximum height gained by pellet on moon = ?

Therefore,

2(1.625 m/s²)h' = (44.27 m/s)² - (0 m/s)²

h' = (1960 m²/s²)/(3.25 m/s²)

<u>h' = 603.08 m</u>

4 0
3 years ago
A rocket sled is tested at "5 g" (5 times the acceleration due to gravity). If the sled starts from rest at position do= 0.00, h
stealth61 [152]
D=at²
441m=(5*9.81m/s²)(t²)
t²=441/(5*9.81)
t≈√8.99
t≈3 sec
8 0
3 years ago
Read 2 more answers
A rock is lifted by a machine to a height of 10m. If it has a mass of 22 kilograms
zmey [24]

Answer:

2156J

Explanation:

Given parameters:

Height of lift  = 10m

Mass  = 22kg

Unknown:

Work done by the machine  = ?

Solution:

Work done is the force applied to move a body through a certain distance.

So;

        Work done  = Force x distance

Here;

       Work done  = mass x acceleration due to gravity x height

      Work done  = 22 x 9.8 x 10  = 2156J

5 0
3 years ago
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