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4 years ago

You arrive in my class 45 seconds after leaving math which is 90 meters away. How fast did you travel?

Physics

1 answer:

pashok25 [27]4 years ago

4 0

Answer:

2m/s

Explanation:

speed = distance÷time

speed =90÷45=2m/s

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What does m represent in the equation m = M+ 5 log(d/10)

melisa1 [442]

The lower case m =Apparent magnitude

5 0

3 years ago

What is the metric unit for distance?

Gemiola [76]

Answer:

meters

Explanation:

4 0

4 years ago

Two ice skaters, Daniel (mass 70.0 kg) and Rebecca (mass 45.0 kg), are practicing. Daniel stops to tie his shoelace and, while a

Ivan

Answer:

The magnitude of Daniel's velocity after collision is 6.84 m/s.

Explanation:

Given that,

Mass of Daniel = 70.0 Kg

Mass of Rebecca = 45.0 kg

Initial speed of Rebecca= 13.0 m/s

Final speed of Rebecca = 6.00 m/s

Angle = 54.1°

Suppose we need to calculate the magnitude of Daniel's velocity after the collision

We need to calculate the velocity of Daniel along x axis

Using conservation of momentum

$m_{d}u_{d}+m_{r}u_{r}=m_{d}v_{d}+m_{r}v_{r}\cos\theta$

Put the value into the formula

$0+45\times13.0=70\times v_{x}+45\times6\cos54.1$

$v_{x}=\dfrac{45\times13-45\times6\cos54.1}{70}$

$v_{x}=6.09\ m/s$

We need to calculate the velocity of Daniel along y axis

Using conservation of momentum

$m_{d}u_{d}+m_{r}u_{r}\sin\theta=m_{d}v_{d}+m_{r}v_{r}$

Put the value into the formula

$0+45\times6.00\sin54.1=70\times v_{y}+0$

$v_{y}=\dfrac{45\times6.00\sin54.1}{70}$

$v_{y}=3.12\ m/s$

We need to calculate the magnitude of velocity after collision

Using formula of velocity

$v=\sqrt{v_{x}^2+v_{y}^2}$

Put the value into the formula

$v=\sqrt{(6.09)^2+(3.12)^2}$

$v=6.84\ m/s$

Hence, The magnitude of Daniel's velocity after collision is 6.84 m/s.

3 0

3 years ago

A newly discovered particle, the SPARTYON, has a mass 455 times that of an electron. If a SPARTYON at rest absorbs an anti-SPART

algol [13]

Answer:

υ = 5.62 x 10¹⁴ Hz

Explanation:

The process of of formation of photons takes place due to interaction of a particle with its anti-particle is called Annihilation of Matter. Here SPARTYON absorbs anti-SPARYTON to form 2 photons. Applying conservation of energy to the to this scenario, we get:

2(Energy of Each Photon) = Rest Mass Energy of SPARTYON + Rest Mass Energy of anti-SPARTYON

$2hv = m_{0}c^2 + m_{0}c^2\\\\2hv = 2m_{0}c^2\\\\hv = m_{0}c^2\\\\v = \frac{m_{0}c^2}{h}$

where,

υ = frequency of each photon = ?

m₀ = rest mass of SPARTYON = mass of anti-SPARTYON = 455*Mass of electron

m₀ = 455(9.1 x 10⁻³¹ kg) = 4.14 x 10⁻²⁸ kg

c = speed of light = 3 x 10⁸ m/s

h = Plank's Constant = 6.625 x 10⁻³⁴ J.s

Therefore, using these values in the equation, we get:

$v = \frac{(4.14 x 10^{-28} kg)(3 x 10^8 m/s)^2}{6.625 x 10^{-34}J.s}\\\\$

5 0

3 years ago

Two soccer players kick the same 1-kg ball at the same time in opposite directions. One kicks with a force of 25 N; the other ki

andre [41]

Answer:

The forces offset to produce a net force of 8 N

since the ball is 1 kg

F = ma

a = f/m = 8 N/1 kg = 8 (kg m)/(s^2 kg) = 8 m/s^2

5 0

3 years ago

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