For the circle with equation (x-2)^2+(y+3)^2=9, answer each question. a) whats coords of the center? b) what are the radius and

Question

3 years ago

5

diameter of the circle? c) graph.

1 answer:

MrRissso [65] · Answer 1 · 2022-06-11T00:21:50+03:00

4 0

Answer:

<h2>a) center (2, -3)</h2><h2>b) radius r = 3</h2><h2>c) in the attachment</h2>

Step-by-step explanation:

The standard form of an equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have:

$(x-2)^2+(y+3)^2=9\\\\(x-2)^2+(y-(-3))^2=3^2$

a) center (2, -3)

b) radius r = 3

c) in the attachment