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cluponka [151]
3 years ago
8

What is a basic requirement that a scientific hypothesis must have

Chemistry
1 answer:
Karolina [17]3 years ago
4 0
And "if/then" statement.
Ex. IF I add this amount of water to my plant everyday, THEN it will grow into a healthy plant.
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Instructions: Select the correct answer.
drek231 [11]
The answer is going to be C. Although producing at a fast rate, fossil fuel cannot be re-used or recycled. Wind can be re-used, geothermal energy can be re-used, and hydro energy can be re-used.

Hope this Helps! :)
3 0
4 years ago
Convert 11.7 mL to cL
belka [17]
Answer: 11.7 mL=1.17 cL
5 0
3 years ago
How heat moves from one end of a solid to another
pantera1 [17]
In conduction, the thermal energy of a particle is transferred to other particles throughout the solid. The particles with more energy are transferred to those with less.
3 0
4 years ago
Based on the recipe for the Dextrose Calcium Carbonate (DCC) medium, what is the percent concentration (%weight/volume) of dextr
yanalaym [24]

<u>Answer:</u> The percent concentration ( % m/v) of dextrose in the solution is 2 %

<u>Explanation:</u>

We are given:

Mass of Yeast Extract = 5.0 grams

Mass of K_2HPO_4 = 1.0 grams

Mass of MgSO_4 = 0.5 grams

Mass of Dextrose = 20.0 grams

Mass of CaCO_3 = 10. grams

Mass of Agar = 18.0 grams

Volume of solution = 1 L = 1000 mL      (Conversion factor: 1 L = 1000 mL)

% (m/v) is defined as the concentration, which is mass of solute present in 100 mL of solution

To calculate the mass of solute, we apply unitary method:

In 1000 mL of solution, the mass of dextrose present is 20.0 grams

So, in 100 mL of solution, the mass of dextrose present will be = \frac{20.0}{1000}\times 100=2g

Calculating the % (m/v) of dextrose, we get:

\% \text{(m/v) of dextrose}=\frac{\text{Mass of dextrose}}{\text{Volume of solution}}\times 100\\\\\% \text{(m/v) of dextrose}=\frac{2g}{100mL}\times 100=2\%

Hence, the percent concentration ( % m/v) of dextrose in the solution is 2 %

4 0
4 years ago
could you please explain operations with scientific notation using this example. 5 × 10³ + 4.3 × 10⁴ i dont understand how to so
TEA [102]

Explanation:

The scientific notation:

a\times10^k

where

1\leq a and k is integer.

We have the example:

(5\times10^3)+(4.3\times10^4)

You can write the numbers in a "normal" form:

5\times10^3=5\times1000=5000\\\\4.3\times10^4=4.3\times10000=43000

Make the sum:

5000+43000=48000

And next write it in the scientific notation:

48000=4\underbrace{8000}_{\leftarrow4}=4.8000\times10000=4.8\times10^4

<h3>Other method:</h3>

You can add numbers in scientific notation if the power of tens in both number is the same.

Therefore you must convert the first number:

5\times10^3=0.5\times10\times10^3=0.5\times10^4

Now, you can make the sum:

(5\times10^3)+(4.3\times10^4)=0.5\times10^4+4.3\times10^4=(0.5+4.3)\times10^4=4.8\times10^4

4 0
3 years ago
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