According to law of conservation of matter and energy, amount of both of them will remain same
Answer:
D) 0.450 M
Explanation:
Given data
- Initial volume (V₁): 6.00 mL
- Initial concentration (C₁): 0.750 M
- Volume of water (VH₂O): 4.00 mL
- Final volume (V₂): V₁ + VH₂O = 6.00 mL + 4.00 mL = 10.0 mL
- Final concentration (C₂): ?
We can determine the final concentration using the dilution rule.
C₁ × V₁ = C₂ × V₂
C₂ = C₁ × V₁/V₂
C₂ = 0.750 M × 6.00 mL/10.0 mL
C₂ = 0.450 M
Moles of water atoms = mass/molecular weight = 105/18 = 5.83 mol. Number of moles of hydrogen in water = 2 x moles of water = 11.66. Number of H atoms in water = moles of hydrogen x 6.02 x 10^23 = 7.019 x 10^24 ~ 7.02 x 10^24 atoms. Hope this helps.