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Firdavs [7]
3 years ago
11

Identify the type of chemical reaction of cobalt (III) fluoride

Chemistry
1 answer:
zysi [14]3 years ago
4 0

The compound crystallizes in the aluminium trifluoride motif. Each fluoride is a doubly bridging ligand. The cobalt centers are octahedral.


CoF3 decomposes upon contact with water to give oxygen:


4 CoF3 + 2 H2O → 4 HF + 4 CoF2 + O2

It reacts with fluoride salts to give the anion [CoF6]3−, which is also features high-spin, octahedral cobalt(III) center.

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Sulfuric acid is formed when sulfur dioxide reacts with oxygen and water. Write a balanced chemical equation for the reaction. (
Nesterboy [21]

Balanced chemical equation for the reaction is:

2SO_{2} (g) + O_{2} (g)+ 2H_{2}O (l) ⇒H_{2} S_{} O_{4}

Moles of H_{2} S_{} O_{4} formed is 5.75 moles.

Moles of oxygen used is 5.75 moles in the reaction.

Explanation:

Data given:

moles of SO_{2} = 11.5 moles

moles of H_{2} S_{} O_{4} = ?

Moles of O_{2} needed =?

balanced equation with states of matter =?

Balanced chemical reaction under STP condition is given as:

2SO_{2}(g) + O_{2} (g) + 2H_{2}O (l) ⇒H_{2} S_{} O_{4}

From the balanced reaction 2 moles of sulphur dioxide reacted to form 1 mole of sulphuric acid:

so, from 11.5 moles of SO_{2}, x moles of H_{2} S_{} O_{4} is formed

\frac{1}{2}  =\frac{x}{11.5}

2x = 11.5

x = 5.75 moles of sulphuric acid formed.

From the balanced reaction 1 mole of oxygen reacted to form 1  mole of sulphuric acid.

when 11.5 moles of Sulphur dioxide reacted then oxygen in the reaction is 5.75 moles.

7 0
3 years ago
3) Which pair of formulas represents the empirical formula and molecular
Alexxx [7]

Answer:

The answer to your question is maybe letter D, but the last oxygen needs a number 6.

Explanation:

The empirical formula gives the actual elements that form part of a molecule but not the total numbers.

The molecular formula gives the total number of atoms of each element in a molecule.

We must factor the molecular formula to know if a formula is the empirical formula of that.

A.        CH₄    C₂H₆  =  2(CH₃)       these are not empirical molecular formulas

B.        CH₂O  C₄H₆O                     these are not empirical-molecular formulas      

C.        O₂        O₃                           these are not empirical-molecular formulas

D.        C₃H₄O₃   C₆H₈O                 these are not empirical-molecular formulas

                                                       the last oxygen needs a number 6 to be

                                                       the answer.

6 0
3 years ago
Read 2 more answers
In 1676, Robert Plot discovered a large bone in a quarry in Cornwall, England. He observed that the bone looked similar to a hum
sergeinik [125]

Answer:

D

Explanation:

4 0
3 years ago
IS THISS RIGHTTTTT???
shtirl [24]

Answer: No

Explanation: For it to be a divergent boundary, the arrows would have to be pointing in opposite directions. (one points left, one points right).

3 0
3 years ago
Read 2 more answers
If 125 ml of o2 gas exerts a pressure of 1.0 atm inside a cylinder, what will the pressure be if the cylinder compressed the vol
Lelu [443]
<h2>Hello!</h2>

The answer is: The new pressure is 1.67 atm.

<h2>Why?</h2>

From the statement, we know that the temperature remains constant and the gas volume is changing, meaning that the new pressure will be different than the first pressure.

Since the temperature remains constant, we can calculate the new pressure using the Boyle's Law.

The Boyle's Law states that:

P_{1}V_{1}=P_{2}V_{2}

Where,  

P is the pressure of the gas.

V is the volume of the gas.

Then, the given information is:

V_{1}=125ml=0.125L\\P_{1}=1atm\\V_{2}=75ml=0.075L

Remember, 1 L is equal to 1000 mL.

So,

125mL*\frac{1L}{1000mL}=\frac{125mL*1L}{1000mL}=0.125L\\\\75mL*\frac{1L}{1000mL}=\frac{75mL*1L}{1000mL}=0.075L

So, calculating the new volume, we have:

P_{1}V_{1}=P_{2}V_{2}\\\\1atm*0.125L=P_{2}*0.075L\\\\P_{2}=\frac{1atm*0.125L}{0.075l}=1.67atm

Hence, the new pressure is 1.67 atm.

Have a nice day!

7 0
3 years ago
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