A displacement is a vector quantity that takes into account the shortest distance from the starting point to the endpoint.
The given above gave a time interval in minutes which needs to be converted to seconds. Given that each minute is 60 seconds, 5 minutes equal 300 seconds. To determine the distance, multiply time with speed. The product is 225 m.
Thus, the displacement is 225 m.
Answer: The height above the release point is 2.96 meters.
Explanation:
The acceleration of the ball is the gravitational acceleration in the y axis.
A = (0, -9.8m/s^)
For the velocity we can integrate over time and get:
V(t) = (9.20m/s*cos(69°), -9.8m/s^2*t + 9.20m/s^2*sin(69°))
for the position we can integrate it again over time, but this time we do not have any integration constant because the initial position of the ball will be (0,0)
P(t) = (9.20*cos(69°)*t, -4.9m/s^2*t^2 + 9.20m/s^2*sin(69°)*t)
now, the time at wich the horizontal displacement is 4.22 m will be:
4.22m = 9.20*cos(69°)*t
t = (4.22/ 9.20*cos(69°)) = 1.28s
Now we evaluate the y-position in this time:
h = -4.9m/s^2*(1.28s)^2 + 9.20m/s^2*sin(69°)*1.28s = 2.96m
The height above the release point is 2.96 meters.
Answer:
trigonometry (guessing)
Explanation:
ellipse: is the shape of an orbit : looks like an oval
periapsis : shortest distance between something like the moon and the planet its orbiting around like the earth
parallax is triangulation. like how gps works. looking at a star one day and then looking at it again 6 months later, an astronomer can see a difference in the viewing angle for the star. With trigonometry, the different angles yield a distance. This technique works for stars within about 400 light years of earth
https://science.howstuffworks.com/question224.htm
By comparing the intrinsic brightness to the star's apparent brightness we can calculate the distance of stars
1/r^2 rule states that the apparent brightness of a light source is proportional to the square of its distance.Jan 11, 2022
https://www.space.com/30417-parallax.html
alternative distance measurement for stars used by most astronomers is the parsec. A star with a parallax angle of 1 arcsecond has a distance of 1 parsec, or 1 parsec per arcsecond of parallax, which is about 3.26 light years
blossoms.mit.edu
.
Answer:
The deceleration is 0.18 m/s²
Explanation:
Hi there!
Using Newton´s second law, we can calculate the deceleration:
∑F = m · a
Where:
∑F = the sum of all forces in a given direction.
m = mass of the object.
a = acceleration.
Solving for a:
∑F/m = a
The only force acting on the meteor is the applied force of 8.6 N. So, the acceleration will be:
8.6 N / 48.9 kg = a
a = 0.18 m/s²
The deceleration is 0.18 m/s² or, in other words, the acceleration is -0.18 m/s²
Have a nice day!
13.6g
136g
Explanation:
Given parameters:
Density of mercury = 13.6g/cm³
Unknown:
Mass of :
1cm³ of mercury
10cm³ of mercury
Solution:
Density is the mass per unit volume of a substance. It is the amount of matter in a given volume.
Density = 
Since the unknown in the problem is mass;
Mass = density x volume
Mass of 1cm³ of mercury = 13.6 x 1 = 13.6g
Mass of 10cm³ of mercury = 10 x 13.6 = 136g
learn more:
Density problems brainly.com/question/3433940
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