All categories

3 years ago

A copper telephone wire has essentially

Physics

1 answer:

Lunna [17]3 years ago

5 0

Answer:

128.21 m

Explanation:

The following data were obtained from the question:

Initial temperature (θ₁) = 4 °C

Final temperature (θ₂) = 43 °C

Change in length (ΔL) = 8.5 cm

Coefficient of linear expansion (α) = 17×10¯⁶ K¯¹)

Original length (L₁) =.?

The original length can be obtained as follow:

α = ΔL / L₁(θ₂ – θ₁)

17×10¯⁶ = 8.5 / L₁(43 – 4)

17×10¯⁶ = 8.5 / L₁(39)

17×10¯⁶ = 8.5 / 39L₁

Cross multiply

17×10¯⁶ × 39L₁ = 8.5

6.63×10¯⁴ L₁ = 8.5

Divide both side by 6.63×10¯⁴

L₁ = 8.5 / 6.63×10¯⁴

L₁ = 12820.51 cm

Finally, we shall convert 12820.51 cm to metre (m). This can be obtained as follow:

100 cm = 1 m

Therefore,

12820.51 cm = 12820.51 cm × 1 m / 100 cm

12820.51 cm = 128.21 m

Thus, the original length of the wire is 128.21 m

You might be interested in

Need help asap please and thank you

nordsb [41]

Distance = speed x time

distance = 116 x 10

distance = 1160 m

6 0

3 years ago

5b) how fast is the car going after 6 seconds?

jeka94

Answer:

No imageeeeeeeeeeeeeeeeeeeeee

8 0

3 years ago

Read 2 more answers

1. li took 2 } seconds for a car's vclocity to change from 20 m/s to 15 m/s. The mass of the car was 1370 kg. What force was req

Pani-rosa [81]

Answer:

Do you still need help??

Explanation:

3 0

2 years ago

How long does it take a microwave of power 0.2kW to sue 10000 J of energy

olasank [31]

Answer:

50s .

Explanation:

$\frak{\pink{Given}}\begin{cases}\textsf{ The power of microvave is 0.2kW .}\\\textsf{ Amount of energy is 10000 J .}\end{cases}$

Here the power of the microwave is 0.2kW . And as we know that ,

Rate of doing work is called power .

So from the definition , we have ;

$\sf\longrightarrow Power =\dfrac{Work}{time}$

Here the work done is equal to the energy consumed by the microwave i.e. 10000 J .So we can write it as ,

$\sf\longrightarrow Power =\dfrac{Energy}{time}$

$\sf\longrightarrow 0.2kW = \dfrac{10^4 J }{t} \\$

$\sf\longrightarrow 0.2 * 1000 W = \dfrac{10^4 J }{t}$

Cross multiply ,

$\sf\longrightarrow t = \dfrac{ 10^4 }{ 0.2 * 10^3}s=\dfrac{10^4}{2*10^2} s$

Simplify ,

$\sf\longrightarrow \boxed{\bf t = 50s}$

<h3>Hence the time taken is 50s .</h3>

5 0

1 year ago

A solid cylindrical object has a mass of 2.0 kg, a diameter

omeli [17]

Answer:

I = 0.0025 kg.m²

Explanation:

Given that

m= 2 kg

Diameter ,d= 0.1 m

Radius , $R=\dfrac{d}{2}$

$R=\dfrac{0.1}{2}$

R=0.05 m

The moment of inertia of the cylinder about it's axis same as the disc and it is given as

$I=\dfrac{mR^2}{2}$

Now by putting the all values

$I=\dfrac{2\times 0.05^2}{2}$

I = 0.0025 kg.m²

Therefore we can say that the moment of inertia of the cylinder will be 0.0025 kg.m².

4 0

3 years ago