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MissTica
3 years ago
14

A freight train is accelerating on a level track. The tension in the coupling between the engine and the first freight car would

change if some of the cargo in the last car were transfered to other cars?
Physics
1 answer:
rewona [7]3 years ago
6 0

Answer:

False

Explanation:

According to Newton's 3rd law, the tension between the engine and the 1st freight cars would equals to the force required to pull all the freight cars from the 1st one on ward. In addition, Newton's 2nd law states that the F = ma, which means that force is proportional to the mass of all the freight cars, given that the freight train is accelerating. So if some of the cargo in the last car were transferred to other cars, their total mass would stay the same, and so as force F and tension.

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Answer:

anions

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The other are families of the periodic table.

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A pressure that will support a column of Hg to a height of 256 mm would support a column of water to what height? The density of
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Answer:

<em>The height of water in the column = 348.14 cm</em>

Explanation:

<em>Pressure:</em><em>This is defined as the ratio of the force acting normally ( perpendicular) to the area of surface in contact. The S.I unit of  pressure is N/m²</em>

<em>p = Dgh............... Equation 1</em>

<em>Where p = pressure, D = density, g = acceleration due to gravity, h = height.</em>

<em>From the question, the same pressure will support the column of mercury and water.</em>

<em>p₁ = p₂</em>

<em>Where p₁ = pressure of mercury, p₂ = pressure of water</em>

D₁gh₁ = D₂gh₂.................. Equation 2

making h₂ the subject of equation 2

h₂ = D₁gh/D₂g............... Equation 3

Where D₁ and D₂ = Density of mercury and water respectively, h₁ and h₂ = height of mercury and water respectively

Given: D₁ = 13.6 g/cm³, D₂ = 1.00 g/cm³, h₁ = 256 mm = 25.6 cm.

Constant: g = 9.8 m/s²

Substituting these values into Equation 3,

h₂ = (13.6×9.8×25.6)/1×9.8

<em>h₂ = 348.14 cm</em>

<em>The height of water in the column = 348.14 cm</em>

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A mechanic uses a jack to lift up a car. He exerts a force of 11,000 N at a distance of 3m from the axis of rotation. How much t
pshichka [43]

Answer:

<h2>The amount of torque put on the car is 33,000Nm</h2>

Explanation:

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