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guajiro [1.7K]
4 years ago
13

Gravitational force acts on two objects with which attribute? A. mass B. force C. orbit D. speed

Chemistry
2 answers:
Reptile [31]4 years ago
7 0
The answer is A. mass. I hope I could help. :)
Svetlanka [38]4 years ago
5 0
It is force I believe
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What is subshell notation
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All electrons in an atom are placed into shells according to electron energies. ... The ground state is determined by always placing each electron into the lowest energy subshell<span>. 

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3 years ago
Why is it not recommended to use red, yellow or blue in the chromatography lab? Explain your reasoning in at least two sentences
bazaltina [42]

Answer:

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3 years ago
How many nuclei of 238 92 U 92 238 U remain in a rock if the activity registers 290 decays per second?(Note that the half life o
Rom4ik [11]

Answer:

Use the activity formula,  

T1/2 = 4.468 x 10^9 yr x 365 x 24 x 3600 = 1.409 x 10^17 sec  

l = ln(2)/T1/2 = ln(2)/1.409 x 10^17 = 4.91932697 x 10^-18 s-1  

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7 0
3 years ago
- a) write the formula unit of calcium fluoride.
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Answer:

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5 0
3 years ago
A mass spectrum of an organic compound shows the relative abundances of M to be 40.58% and M 1 to be 7.022%. Assuming the peaks
sveticcg [70]

Answer:

The number of carbon atoms in the organic compound is 16.

Explanation:

The relative intensity of M + 1 peak (relative to M = 100) in organic compounds can be predicted by the following formula:

[M + 1] = (number of C x 1.07) ---------------------------------------------------- (1)

This formula can also be used to determine the number of carbon from the given intensity. But first, the intensity of [M + 1] relative to [M] = 100 needs to be determined, for which, consider the following calculations,

[M+1]=(\frac{M+1}{M}) (100)

[M+1]=(\frac{7.022}{40.58}) (100)

[M+1]=17.30

Using equation 1 we get,

number of C=\frac{[M+1]}{1.07}

number of C=\frac{17.3}{1.07}\\number of C = 16.168

or number of C = 16

The remaining value, 0.168, can be due to the isotopes of hydrogen and oxygen in the organic compound.

7 0
4 years ago
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