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2 years ago

For a phase change, H0 = 2 kJ/mol and A S0 = 0.017 kJ/(K•mol). What are

Chemistry

1 answer:

34kurt2 years ago

8 0

Answer:

ΔG = -6.5kJ/mol at 500K

Explanation:

We can find ΔG of a reaction using ΔH, ΔS and absolute temperature with the equation:

ΔG = ΔH - TΔS

Computing the values in the problem:

ΔG = ?

ΔH = 2kJ/mol

T = 500K

And ΔS = 0.017kJ/(K•mol)

Replacing:

ΔG = 2kJ/mol - 500K*0.017kJ/(K•mol)

ΔG = 2kJ/mol - 8.5kJ/mol

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A certain compound is made up of one phosphorus (P) atom, three chlorine (Cl) atoms, and one oxygen (O) atom. What is the chemic

user100 [1]

<span> POCl3 is the correct way to write the chemical formula for this compound</span>

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3 years ago

The atomic masses of the two stable isotopes of boron; boron-10 (natural abundance:19.78%) and boron-11 (natural abundance:80.22

iogann1982 [59]

(19.78 x 10) + (80.22 x 11) all of them divided by 100= 10.81 amu

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3 years ago

Ideal gas (n 2.388 moles) is heated at constant volume from T1 299.5 K to final temperature T2 369.5 K. Calculate the work and h

bija089 [108]

Answer : The work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

Explanation :

(a) At constant volume condition the entropy change of the gas is:

$\Delta S=-n\times C_v\ln \frac{T_2}{T_1}$

We know that,

The relation between the $C_p\text{ and }C_v$ for an ideal gas are :

$C_p-C_v=R$

As we are given :

$C_p=28.253J/K.mole$

$28.253J/K.mole-C_v=8.314J/K.mole$

$C_v=19.939J/K.mole$

Now we have to calculate the entropy change of the gas.

$\Delta S=-n\times C_v\ln \frac{T_2}{T_1}$

$\Delta S=-2.388\times 19.939J/K.mole\ln \frac{369.5K}{299.5K}=-10J$

(b) As we know that, the work done for isochoric (constant volume) is equal to zero. $(w=-pdV)$

(C) Heat during the process will be,

$q=n\times C_v\times (T_2-T_1)=2.388mole\times 19.939J/K.mole\times (369.5-299.5)K= 3333.003J$

Therefore, the work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

7 0

3 years ago

How many moles of Mg3(PO4)2 are in 350.00 grams of Mg3(PO4)2?

dusya [7]

Answer:

1.3 moles/ 1.33150727 moles

Explanation:

350g x 1 mol/262.86g = 1.3 moles

6 0

2 years ago

Read 2 more answers

What kind of bond is formed between hydrogen and chlorine atoms?

SVETLANKA909090 [29]

Answer:

The answer to your question is Covalent

Explanation:

Both, Hydrogen and Chlorine are non metals, when two nonmetals attach the share electrons and the type of bonding formed is polar covalent because they have different sizes, hydrogen is smaller than chlorine.

7 0

2 years ago