Answer:
carbon dioxide is acidic and when it comes in contact with blue litmus paper it turns red
Explanation:
Answer:
The answer to your question is it is not at equilibrium, it will move to the products.
Explanation:
Data
Keq = 2400
Volume = 1 L
moles of NO = 0.024
moles of N₂ = 2
moles of O₂ = 2.6
Process
1.- Determine the concentration of reactants and products
[NO] = 0.024 / 1 = 0.024
[N₂] = 2/1 = 2
[O₂] = 2.6/ 1= 2.6
2.- Balanced chemical reaction
N₂ + O₂ ⇒ 2NO
3.- Write the equation for the equilibrium of this reaction
Keq = [NO]²/[N₂][O₂]
- Substitution
Keq = [0.024]² / [2][2.6]
-Simplification
Keq = 0.000576 / 5.2
-Result
Keq = 1.11 x 10⁻⁴
Conclusion
It is not at equilibrium, it will move to the products because the experimental Keq was lower than the Keq theoretical-
1.11 x 10⁻⁴ < 2400
2H₂ + O₂ = 2H₂O
n(H₂)=m(H₂)/M(H₂)
n(H₂)=5g/2.0g/mol=2.5 mol
n(O₂)=m(O₂)/M(O₂)
n(O₂)=40g/32.0g/mol=1.25 mol
H₂ : O₂ = 2 : 1
2.5 : 1.25 = 2 : 1
n(H₂O)=n(H₂)=2n(O₂)=2.5 mol
m(H₂O)=n(H₂O)M(H₂O)
m(H₂O)=2.5mol*18.0g/mol=45.0 g
This statement would be considered false.
Answer:
1033.36g
Explanation:
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10^23 molecules. This means that 1 mole of SO2 also contains 6.02x10^23 molecules.
1 mole SO2 = 32 + (16x2) = 64g.
Now, If 64g of SO2 contains 6.02x10^23 molecules,
Therefore, Xg of SO2 will contain 9.72x10^24 i.e
Xg of SO2 = (64x9.72x10^24)/6.02x10^23
Xg of SO3 = 1033.36g.
Therefore, 1033.36g of SO2 contains 9.72x10^24 molecules
