Given that :
Power (P) = 30 W ,
time (t) = 40 s,
Work = ?
we know that, power is defined as rate of doing work
Power = Work ÷ time
=> Work = Power × time
= 30 × 40
<em> W = 1200 J</em>
It’s D. An enlargement (hope this helps!)
Answer:
35.5KJ
Explanation:
Heat transferred (Q) = change in internal energy (∆U) + work done (W)
Q = 30KJ, W = 500Nm = 500J = 500/1000KJ = 0.5KJ
∆U = Q - W = 30 - 0.5 = 25.5KJ
∆U = final energy (U2) - initial energy (U1)
U2 = ∆U + U1 = 25.5 + 10 = 35.5KJ
Answer: 207 W
Explanation: I assumed here that the object is moved vertically. If that is the case, the work done on the object is equal to its change in gravitational potential energy:
where
m = 47 kg is the mass of the object
g = 9.8 m/s^2 is the acceleration of gravity
is the change in height
Substituting,
Now we can calculate the power used, which is given by
Hope this helps I'm sorry if i'm wrong but I tried :(
Answer:
Explanation:
Given
mass of box is m
speed of box is v
coefficient of friction
Box is moving at a constant speed i.e. Net Force on box is zero
i.e. Frictional Force and Force Applied are Equal
The Rate at which power is generated is