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Sidana [21]
2 years ago
6

Please Help!!!!

Physics
1 answer:
oee [108]2 years ago
7 0
I think is limestone
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Three +3.0-μC point charges are at the three corners of a square of side 0.50 m. The last corner is occupied by a −3.0-μC charge
Naddik [55]

Answer:

4.30 x 10⁵ N/C

Explanation:

Two positive +3.0-μC point charges at opposite corners of the square creates equal and opposite electric field at the center. hence the electric field by these two positive charges at opposite corners becomes zero.

a = length of the square of side = 0.50 m

r = distance of the center from each corner = \frac{a}{sqrt(2)} = \frac{0.50}{sqrt(2)} = 0.354 m

Magnitude of net electric field at the center is given as

E = \frac{2kq}{r^{2}} \\E = \frac{2(8.99\times10^{9})(3\times10^{-6})}{(0.354)^{2}} \\E = 4.30\times10^{5} NC^{-1}

6 0
3 years ago
A 4 kg textbook sits on a desk. It is pushed horizontally with a 50 N applied force against a 15 N frictional force.
ikadub [295]

Answer:

b) No acceleration in the vertical

c) 35N

d) 35N

e) 8.75\ m/sec^2

Explanation:

a) The situation can be shown in the free body diagram shown in the figure below where F is the applied force, Fr is the friction force, W is the weight of the book and N is the normal force exerted vertically up from the desk to the book

b) The vertical movement is restrained by the normal force which opposes to the weight. In absence of any other force, they both are in equilibrium and the net force is zero

c) The net horizontal force acting on the book is the vectorial sum of the applied force and the friction force. Since they lie in the same axis and are opposed to each other:

Fh_{net}=F-F_r=50 N - 15N=35N

d) The net force acting on the book is the vector sum of all forces in all axes. The normal and the weight cancel each other in the y-axis, so our resulting force is the x-axis net force, computed as above:

F_n=35N in the x-axis

e) Following Newton's second law, the acceleration is calculated as

a=\frac{F_t}{m}=\frac{35N}{4Kg}=8.75m/sec^2

8 0
2 years ago
HELP ME OUT PLEASE!!!!!
Nataliya [291]

Answer:

B and D is the answer

Explanation:

I took the assignment <3

3 0
2 years ago
Read 2 more answers
A ball has mass of 140g. what is the force to accelerate the ball at 25m/s
Fittoniya [83]

We know, F = m * a

Here, m = 140 g = 0.140 Kg

a = 25 m/s2

It would be: F = 0.140 * 25 = 3.5 N

So your answer would be 3.5N


6 0
3 years ago
Read 2 more answers
Calculate the energy transferred by an appliance using mains electricity (230V) if the charge is 150C. Give your answer in kiloj
Otrada [13]

The energy transferred by the appliance using mains electricity is 17.3 KJ

<h3>Data obtained from the question </h3>
  • Potential difference (V) = 230V
  • Charge (Q) = 150 C
  • Energy (E) =?

<h3>How to determine the energy transferred </h3>

The energy transferred can be obtained as follow:

E = ½QV

E = ½ × 150 × 230

E = 75 × 230

E = 17250 J

Divide by 1000 to express in kilojoules

E = 17250 / 1000

E = 17.3 KJ

Learn more about energy stored in a capacitor:

brainly.com/question/14739936

8 0
2 years ago
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