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Mekhanik [1.2K]
4 years ago
5

I need help with writing the formula compounds by cross crossing them

Chemistry
1 answer:
ElenaW [278]4 years ago
5 0
Use your head or a formula website.
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What is the oxidation number of boron in Na(B(NO3)4)
Vitek1552 [10]

Answer:

the oxidation state od boron in sodium boron hydride is (+3).

7 0
2 years ago
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6
Vanyuwa [196]

Answer:

If the volume of a gas increased from 2 to 6 L while the temperature was held constant, <u><em>the  pressure of the gas decreased by a factor of 3.</em></u>

Explanation:

Boyle's law that says "The volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure." This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

Pressure * Volume = constant

or

P * V = k

To obtain the proportionality factor k you must make the quotient:

k=\frac{V2}{V1} =\frac{6 L}{2 L}

k= 3

This means that <u><em>if the volume of a gas increased from 2 to 6 L while the temperature was held constant, the  pressure of the gas decreased by a factor of 3.</em></u>

4 0
3 years ago
Based on what you have learned about the water cycle, explain 3 ways that life on earth would be impacted if there was no transp
melisa1 [442]

1. The water inside a plant will not be able to come out.

2. It would kill the plants and species on Earth.

3. There would be no lakes, ocean, or water on land.

8 0
3 years ago
A una mezcla de 300g, formada con 60% P/P de Hierro y 40% P/P de Arena, se le adicionan 135g de Cobre y 2,77g de Aluminio. ¿Cuál
Svetllana [295]

Answer:

\%P/P_{hierro}=41.1\%\\\\\%P/P_{arena}=24.4\%\\\\\%P/P_{cobre}=30.8\%\\\\\%P/P_{aluminio}=0.6\%

Explanation:

¡Hola!

En este caso, dado que estamos tratando con problem sobre porcentaje peso/peso de hierro, arena, cobre y aluminio, primero debemos calcular la masa inicial de estos dos primeros en la mezcla original de acuerdo con:

m_{hierro}=300g*0.60=180g\\\\m_{arena}=300*0.40=120g

Ahora si podemos calcular la masa de la mezcla final como la suma de las masas de todos los constituyentes de la mezcla:

m_T=180g+120g+135g+2.77g=437.77g

Finalmente, podemos calcular los porcentajes P/P como se muestra a continuación:

\%P/P_{hierro}=\frac{180g}{437.77g} *100\%=41.1\%\\\\\%P/P_{arena}=\frac{120g}{437.77g} *100\%=24.4\%\\\\\%P/P_{cobre}=\frac{135g}{437.77g} *100\%=30.8\%\\\\\%P/P_{aluminio}=\frac{g}{437.77g} *100\%=0.6\%

¡Saludos!

5 0
3 years ago
How many moles are in 63 g of NH4 (molar mass= 18g)?
sdas [7]

To answer this question, all you to do is to divide the mass by the molar mass and that should get you your moles.

=63g\ NH_{4}\ x\ \frac{1\ mol\ NH_{4}}{18g\ NH_{4}}

<em>= 3.5 mol NH₄</em>

<em></em>

<em></em>

4 0
2 years ago
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