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Aleks04 [339]
3 years ago
14

In a 63.17 g sample of SO3, how many grams are sulfur?

Chemistry
1 answer:
Evgesh-ka [11]3 years ago
4 0

Answer:

25.30 gram

Explanation:

No of moles = given mass / molar mass

No of moles = 63.17/80.06

0.7890 moles

Mass of sulphar = no of moles× molar mass of sulphar

Mass of sulphur = 0.7890×32.065

25.30 gram

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D.radiation that’s the right answer
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Alum is a compound used in a variety of applications including cosmetics, water purification, and as a food additive. It can be
mylen [45]

yield = 52.23 %

Explanation:

We have the following chemical reaction:

2 Al (s) + 2 KOH (aq) + 4 H₂SO₄ (aq) + 10 H₂O → 2 KAl(SO₄)₂·12 (H₂O) (s) + 3 H₂ (g)

mass of aluminium = mass of bottle with aluminium pieces - bottle mass

mass of aluminium = 10.8955 - 9.8981 = 0.9974 g

mass of alum = mass of bottle with final product - bottle mass

mass of alum = 19.0414 - 9.8981 = 9.1433 g

number of moles = mass / molecular weight

number of moles of aluminium = 0.9974 / 27 = 0.03694 moles

number of moles of alum (practical) = 9.1433 / 474 = 0.01929 moles

To calculate the theoretical quantity of alum that should be obtained from 0.03694 moles of aluminium we devise the following reasoning:

if       2 moles of aluminium produce 2 moles of alum

then 0.03694 moles of aluminium produce X moles of alum

X = (0.03694 × 2) / 2 = 0.03694 moles of alum (theoretical)

yield = (practical quantity / theoretical quantity) × 100

yield = (0.01929 /  0.03694) × 100

yield = 52.23 %

Learn more about:

reaction yield

brainly.com/question/7786567

#learnwithBrainly

5 0
3 years ago
The _____ is one of the way paces where North America and Pacific Plates meet.
Morgarella [4.7K]

Answer:

The ring of fire

Explanation:

The ring of fire is where they meet or at the fault lines

8 0
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It’s called revolution
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3 years ago
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1. Graph a wave with an
kiruha [24]

Answer:

y = 5cos(\frac{2\pi }{6} x)

Explanation:

You can put that equation into a program like desmos on your browser and take a screenshot or use windows snippet tool.

Equation of a Wave: y = Acos(((2*pi)/B)x)

or

y = Acos(\frac{2\pi }{B} x)

A = Amplitude

B= Wavelength

5 0
3 years ago
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