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Aleks04 [339]
2 years ago
14

In a 63.17 g sample of SO3, how many grams are sulfur?

Chemistry
1 answer:
Evgesh-ka [11]2 years ago
4 0

Answer:

25.30 gram

Explanation:

No of moles = given mass / molar mass

No of moles = 63.17/80.06

0.7890 moles

Mass of sulphar = no of moles× molar mass of sulphar

Mass of sulphur = 0.7890×32.065

25.30 gram

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steposvetlana [31]

Answer:

resistant hair

Explanation:

a strong compact cuticle makes for the resistance hair

7 0
2 years ago
Help me in my this plzzz ​
eduard

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a is oxidation

b is reduction

c is reduction

d is oxidation

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8 0
3 years ago
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scZoUnD [109]

#6).
Every 1,000 mL makes 1 L
How many 1,000mL are there in  2,800 mL ?
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#7).
The 'perimeter' means the 'distance all the way around'.
You have to know that both sides of a rectangle are the same length,
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So the perimeter of this rectangle is

   (2 yd) + (4.5 yd) + (2.yd) + (4.5 yd) = 13 yd .

Oops.  The problem wants to know the perimeter in feet.
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In order to find the number of feet in 13 yards, you have to
take 3 feet 13 <em><u>times</u></em> .

       (3 feet) times (13)  =  <em>39 feet .</em>

#8).
For this one, you have to know that every 36 inches makes 1 yard.

How many 36 inches are there in 48 inches ?
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#9).
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#10).
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Add up the distances that Omar ran:

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4 0
3 years ago
Mg + 2HCl → MgCl2 + H2
deff fn [24]

Answer:

Explanation:

This is a limiting reactant problem.

Mg(s)

+

2HCl(aq)

→

MgCl

2

(

aq

)

+ H

2

(

g

)

Determine Moles of Magnesium

Divide the given mass of magnesium by its molar mass (atomic weight on periodic table in g/mol).

4.86

g Mg

×

1

mol Mg

24.3050

g Mg

=

0.200 mol Mg

Determine Moles of 2M Hydrochloric Acid

Convert

100 cm

3

to

100 mL

and then to

0.1 L

.

1 dm

3

=

1 L

Convert

2.00 mol/dm

3

to

2.00 mol/L

Multiply

0.1

L

times

2.00 mol/L

.

100

cm

3

×

1

mL

1

cm

3

×

1

L

1000

mL

=

0.1 L HCl

2.00 mol/dm

3

=

2.00 mol/L

0.1

L

×

2.00

mol

1

L

=

0.200 mol HCl

Multiply the moles of each reactant times the appropriate mole ratio from the balanced equation. Then multiply times the molar mass of hydrogen gas,

2.01588 g/mol

0.200

mol Mg

×

1

mol H

2

1

mol Mg

×

2.01588

g H

2

1

mol H

2

=

0.403 g H

2

0.200

mol HCl

×

1

mol H

2

2

mol HCl

×

2.01588

g H

2

1

mol H

2

=

0.202 g H

2

The limiting reactant is

HCl

, which will produce

0.202 g H

2

under the stated conditions.

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7 0
2 years ago
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Which of the following factors is the most in-<br> fluential in the formation of soil?
Shtirlitz [24]
B. climate
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4 0
3 years ago
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