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Aleks04 [339]
2 years ago
14

In a 63.17 g sample of SO3, how many grams are sulfur?

Chemistry
1 answer:
Evgesh-ka [11]2 years ago
4 0

Answer:

25.30 gram

Explanation:

No of moles = given mass / molar mass

No of moles = 63.17/80.06

0.7890 moles

Mass of sulphar = no of moles× molar mass of sulphar

Mass of sulphur = 0.7890×32.065

25.30 gram

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Consider the reaction:
murzikaleks [220]

<u>Answer:</u> The formation of given amount of oxygen gas results in the absorption of 713 kJ of heat.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

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Putting values in above equation, we get:

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For the given chemical equation:

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<u>Sign convention of heat:</u>

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

By Stoichiometry of the reaction:

When 3 moles of oxygen gas is formed, the amount of heat absorbed is 824.2 kJ

So, when 2.594 moles of oxygen gas is formed, the amount of heat absorbed will be = \frac{824.2kJ}{3mol}\times 2.59mol=713kJ

Hence, the formation of given amount of oxygen gas results in the absorption of 713 kJ of heat.

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《HOPE IT WILL HELP YOU 》

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