There are two different ways to understand time and these are:
A. What time is it?
B. How much time?
The examples of these two different ways are:
A. What time is it? The best example that would help us understand and know what time are the clock and the calendar. This gives us the exact hour, minutes and seconds. The calendar tells us the exact day, month and year.
B. How much time? This makes us understand how much time did it take from the starting time. An example for this would be a stopwatch.
Answer : Celestial or azimuth - altitude
Explanation :
Celestial : The celestial coordinates that are analogous to longitude and latitude are called RA and Dec.
RA = Right Ascension
Dec = Declination
RA is the measured in unit of time and Dec is measured in degree.
The equatorial coordinate system is the projection of the latitude and longitude coordinate system on the celestial sphere.
Azimuth - altitude : Azimuth - altitude define the location of an object in the sky.
The altitude is the distance of an object appears to be above the horizon.
The Azimuth of the object is the angular distance along the horizon to the location of the object.
Wooden spoons don't quickly heat to hot temperatures not nearly as fast as metal does. Metal conducts heat faster than wood — if the head of the spoon is in a hot liquid, the handle will get hot faster if it's made out of a metal.
Black hole, it sucks in pretty much everything in its path
Answer:
20.0 cm
Explanation:
Here is the complete question
The normal power for distant vision is 50.0 D. A young woman with normal distant vision has a 10.0% ability to accommodate (that is, increase) the power of her eyes. What is the closest object she can see clearly?
Solution
Now, the power of a lens, P = 1/f = 1/u + 1/v where f = focal length of lens, u = object distance from eye lens and v = image distance from eye lens.
Given that we require a 10 % increase in the power of the lens to accommodate the image she sees clearly, the new power P' = 50.0 D + 10/100 × 50 = 50.0 D + 5 D = 55.0 D.
Also, since the object is seen clearly, the distance from the eye lens to the retina equals the distance between the image and the eye lens. So, v = 2.00 cm = 0.02 m
Now, P' = 1/u + 1/v
1/u = P'- 1/v
1/u = 55.0 D - 1/0.02 m
1/u = 55.0 m⁻¹ - 1/0.02 m
1/u = 55.0 m⁻¹ - 50.0 m⁻¹
1/u = 5.0 m⁻¹
u = 1/5.0 m⁻¹
u = 0.2 m
u = 20 cm
So, at 55.0 dioptres, the closet object she can see is 20 cm from her eye.
