It is calculated that a)The angular velocity of the wheel is 272.13 rad/s,
b)On the edge of the grinding wheel, the linear speed is 47.62 m/s,
and c) On the edge of the grinding wheel, the acceleration is 12958.08 m/s².
Calculation of angular velocity, linear speed & acceleration:
Provided that,
the diameter of the wheel = 0.35 m
So, the radius, r = 0.35/2 = 0.175 m
As 1 revolution = 2π rad
(a)the angular velocity, ω = 2600 rpm =
rad/s
⇒ω = 272.13 rad/s
So, the angular velocity is 272.13 rad/s.
(b)The linear speed, v = r * ω
⇒v = 0.175 * 272.13
⇒v= 47.62 m/s
(c)The angular acceleration, 
⇒
= 12958.08 m/s²
Learn more about angular velocity here:
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hopefully this helps
Answer:
Explanation:
An example of an intense aerobic activity would be running/ sprinting sprinting targets six specific muscle groups: hamstrings, quadriceps, glutes, hips, abdominals and calves. Sprinting is a total body workout featuring short, high-intensity repetitions and long, easy recoveries.
Answer:
4.3 m/s
Explanation:
Using conservation of momentum, assume that the collision is elastic and that the 3.0 g ball stuck with the carton
3.0 g = 3 / 1000 = 0.003 kg = m₁
40 g = 40 / 1000 = 0.04 kg = m₂, u₂ = 0 since the body is stationary and v = 0.3m/s
m₁u₁ + m₂u₂ = v ( m₁ + m₂)
0.003 u₁ = 0.30 ( 0.003 + 0.04) = 0.0129
u₁ = 0.0129 / 0.003 = 4.3 m/s
Answer:
r = 2,026 10⁹ m and T = 2.027 10⁴ s
Explanation:
For this exercise let's use Newton's second law
F = m a
where the force is electric
F =
Acceleration is centripetal
a = v² / r
we substitute
r =
(1)
let's look for the charge in the insulating sphere
ρ = q₂ / V
q₂ = ρ V
the volume of the sphere is
v = 4/3 π r³
we substitute
q₂ = ρ
π r³
q₂ = 3 10⁻⁹
π 4³
q₂ = 8.04 10⁻⁷ C
let's calculate the radius with equation 1
r = 9 10⁹ 1.6 10⁻¹⁹ 8.04 10⁻⁷ /(9.1 10⁻³¹ 628 10³)
r = 2,026 10⁹ m
this is the radius of the electron orbit around the charged sphere.
Since the orbit is circulating, the speed (speed modulus) is constant, we can use the uniform motion ratio
v = x / t
the distance traveled in a circle is
x = 2π r
In this case, time is the period
v = 2π r /T
T = 2π r /v
let's calculate
T = 2π 2,026 10⁹/628 103
T = 2.027 10⁴ s