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Paladinen [302]
3 years ago
10

Which layer of the sun do we normally see?

Physics
1 answer:
Novay_Z [31]3 years ago
6 0

Answer: <u>The photosphere </u>

<u />

Explanation: It is the solar surface we see when we look at the Sun.

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ou are out stargazing with your 13.4-cm telescope. You point your telescope at an interesting formation in the sky, which you th
Alinara [238K]

Answer:

θ = 4.716 10⁻⁶ rad

Explanation:

In order for the releases to be considered separate, they must meet the Rayleigh criterion that establishes that the maximum diffraction of one star must coincide with the first minimum of the diffraction pattern of the second star.

We use the diffraction equation for a slit

            a sin θ = m λ

The minimum occurs at m = 1

             sin θ = λ / a

Since the angles in these systems are very small, we can approximate the sine to its angle in radians

             θ = λ / a

The telescope has a circular aperture whereby polar cords should be used, which introduces a constant number

           θ = 1.22 λ / a

Let's calculate

          θ = 1.22 518 10⁻⁹ / 13.4 10⁻²

          θ = 4.716 10⁻⁶ rad

8 0
3 years ago
A dog is trained to sit and shake hands these traits are most likely
antiseptic1488 [7]
Taught  not inherited

4 0
3 years ago
2 Name the device in a car that we use to change the speed of the car
Crank

Answer:

Speedometer

Explanation:

Have a good day! :3

6 0
2 years ago
Give two example of conditions when two objects (Object A=1 kg and Object B =10 kg) would have the same momentum.
bearhunter [10]

Answer:

they can have the momentum if only they are been divided by another number to see the difference

6 0
2 years ago
If diameter and length of a cylinder are 0.01 m and 0.07 m respectively, the thermal conductivity of air is 0.028 W/mK and the N
kap26 [50]

Answer:

The convective heat transfer coefficient of the fluid is 170.4 watts per square meter-degree Celsius.

Explanation:

The Nusselt number (Nu) is a dimensionless factor which compares the sensitivity of a fluid due to convection with those due to conduction:

Nu = \frac{h\cdot L_{c}}{k} (Eq. 1)

Where:

h - Convective heat transfer coefficient, measured in watts per square meter-degree Celsius.

k - Conductive heat transfer coefficient, measured in watts per meter-degree Celsius.

L_{c} - Characteristic length, measured in meters.

In addition, the characteristic length of a cylinder is defined by the following formula:

L_{c} = \frac{\pi\cdot r^{3}\cdot l}{2\pi\cdot r^{2}+2\pi\cdot r \cdot l} (Eq. 2)

Where:

r - Radius of the cylinder, measured in meters.

l - Length of the cylinder, measured in meters.

If we know that Nu = 14.2, k = 0.028\,\frac{W}{m\cdot ^{\circ}C}, r = 0.005\,m and l = 0.07\,m, then the convective heat coefficient is:

From (Eq. 2):

L_{c} = \frac{\pi\cdot (0.005\,m)^{2}\cdot (0.07\,m)}{2\pi\cdot (0.005\,m)^{2}+2\pi\cdot (0.005\,m)\cdot (0.07\,m)}

L_{c} = \frac{7}{3000}\,m

And by (Eq. 1):

h = \frac{k\cdot Nu}{L_{c}}

h = \frac{\left(0.028\,\frac{W}{m\cdot ^{\circ}C} \right)\cdot (14.2)}{\frac{7}{3000}\,m }

h = 170.4\,\frac{W}{m^{2}\cdot ^{\circ}C}

The convective heat transfer coefficient of the fluid is 170.4 watts per square meter-degree Celsius.

7 0
2 years ago
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