ALL of the quantities are unknown, because you haven't bothered to tell us anything that's known.
Answer:
Explanation:
a) To get the resistivity ρ at 50 Celsius, given the resitstivity at 20 Celsisus, use:
ρ = ρo(1 + α(T - To))
where To = 20 Celsius
b) Knowing the resistivity at 50 Celsius, and the (uniform) electric field E, you can determine the current density J using:
E = ρJ
(which is actually a density-averaged version of V = IR)
c) Assuming the current is uniform (which is should be in a uniform electric field and constant-diameter wire), the current i can be calculated using:
J = i/A --> i = JA
where A is the cross-sectional area of the wire (given by πr2); make sure to convert the given diameter to a radius, and the radius to base units
d) Since the electric field is given in volts per meter, and you have two meters of length in the wire, you can determine directly from that how many volts difference you need at the ends of the wire to get 0.2 volts per meter.
0.2 = V/d
with d = 2 m. This corresponds to a uniform electric field being related to voltage by V = Ed, where d is distance along the field line.
Answer:
26.822 m/s
Explanation:
60 mi/hr * 5280 ft/mile * 1 hr / 3600 sec * 12 in / foot * 1 meter / 39.37 in = <u>26.822 m/s</u>
Answer:
option A
Explanation:
given,
distance between two masses is doubled
new distance, r' = 3 r
using gravitational force equation
............(1)
new gravitational force
now from the given condition
now, from equation (1)
now, the change in gravitational force factor is equal to 
Hence, the correct answer is option A
