**The height** **below the tower **at which coin 1 pass coin 2 is** 89.04 m**.

**The given parameters:**

height of the tower, h = 100 m

initial velocity of coin 1, v = 15 m/s

time spent in air by coin 1 before coin 2 was dropped = 2s

**To find:**

- the
**height below the tower **at which coin 1 passes coin 2

Find** the maximum height** attained by coin 1 before falling to the ground:

Find **the time taken** for coin 1 to fall to the ground:

Total height of coin 1 above the ground, H = 11.25 m + 100 m = 111.25 m

But the **time taken** for the coin 1 to reach 11.25 m above the tower:

**Total time** **spent by coin 1** before reaching ground **with respect to coin 2:**

**time** = (1.5 s + 4.72 s) - 2 s

**time** = 4.22 s

<u>**Note:**</u><em> the 2 s was subtracted to keep both coins at a fair starting time below the tower</em>.

Find **the total time taken for coin 2 **to fall to the ground:

Height of coin 2 above the ground = 100 m

Total time taken by coin 2 before falling to the ground is calculated as:

The** time** at which coin 1 will pass coin 2 is **4.22 s**.

Find** the height below the tower** when the time is 4.22 s.

Thus, **the height** **below the tower **at which coin 1 pass coin 2 is** 89.04 m**.

Learn more here: brainly.com/question/18943273