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TiliK225 [7]
3 years ago
9

The length of stereocilia actually vary from 10 to 50 micrometers. Again, assuming that they behave like simple pendula, over wh

at frequency range of sound waves would they resonate. (The actual frequency range of human hearing is 20 Hz 20,000 Hz, so might there be other mechanisms involved and/or might the pendular model be rather oversimplified?)
A. About 70 Hz -160 Hz.
B. About 440 Hz - 1000 Hz.
C. About 20 Hz - 50 Hz.
D. About 0.07 to 0.16 Hz.
Physics
1 answer:
Mila [183]3 years ago
6 0

To solve this problem it is necessary to apply the concepts related to the period based on variables such as gravity, distance and frequency.

By definition, know that the Period is

T_1 = 2\pi \sqrt{\frac{L}{g}}

Where,

L = Length

g = Gravity

At the same time, frequency can be defined as,

f_1 = \frac{1}{T_1}

So using this for 10\mu m we have that,

T_1 = 2\pi \sqrt{\frac{L}{g}}

T_1 = 2\pi \sqrt{\frac{10*10^{-6}}{9.8}}

T_1 = 0.635*10^{-2}s

Then the frequency is

f_1 = \frac{1}{T_1}

f_1 = \frac{1}{0.635*10^{-2}}

f_1 = 157.6\approx 160Hz

For the second length of 50\mu m we have that

T_1 = 2\pi \sqrt{\frac{L}{g}}

T_1 = 2\pi \sqrt{\frac{5*10^{-5}}{9.8}}

T_1 = 1.4*10^{-2}s

Then the frequency is

f_1 = \frac{1}{T_1}

f_1 = \frac{1}{1.4*10^{-2}}

f_1 = 70Hz

Therefore the correct answer is A.

You might be interested in
Compounds formed from the attraction of oppositely charged ions are called
Readme [11.4K]

Answer:

Ionic bond

Explanation:

Also called electrovalent bond, type of linkage formed from the electrostatic attraction between oppositely charged ions in a chemical compound.

Hope this helps! brainliest welcomed! :)

8 0
3 years ago
If the mass of a
mixer [17]

Answer:

The final acceleration becomes (1/3) of the initial acceleration.

Explanation:

The second law of motion gives the relationship between the net force, mass and the acceleration of an object. It is given by :

F=ma

m = mass

a = acceleration

According to given condition, if the mass of a  sliding block is tripled while a constant net force is applied. We need to find how much does the acceleration decrease.

a=\dfrac{F}{m}

Let a' is the final acceleration,

a'=\dfrac{F}{m'}

m' = 3m

a'=\dfrac{F}{3m}

a'=\dfrac{1}{3}\times \dfrac{F}{m}

a'=\dfrac{1}{3}\times a

So, the final acceleration becomes (1/3) of the initial acceleration. Hence, this is the required solution.

5 0
3 years ago
After being struck by a bowling ball, a 1.8 kg bowling pin sliding to the right at 5.0 m/s collides head-on with another 1.8 kg
kaheart [24]

Answer:

a) v₂ = 4.2 m/s

b) v₂ = 5 m/s

Explanation:

a)

We will use the law of conservation of momentum here:

m_1u_1+m_2u_2=m_1v_1+m_2v_2

where,

m₁ = m₂ = mass of bowling pin = 1.8 kg

u₁ = speed of first pin before collsion = 5 m/s

u₂ = speed of second pin before collsion = 0 m/s

v₁ = speed of first pin after collsion = 0.8 m/s

v₂ = speed of second after before collsion = ?

Therefore,

(1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0.8\ m/s)+(1.8\ kg)(v_2)\\v_2 = 5\ m/s - 0.8\ m/s

<u>v₂ = 4.2 m/s</u>

<u></u>

b)

We will use the law of conservation of momentum here:

m_1u_1+m_2u_2=m_1v_1+m_2v_2

where,

m₁ = m₂ = mass of bowling pin = 1.8 kg

u₁ = speed of first pin before collsion = 5 m/s

u₂ = speed of second pin before collsion = 0 m/s

v₁ = speed of first pin after collsion = 0 m/s

v₂ = speed of second after before collsion = ?

Therefore,

(1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0\ m/s)+(1.8\ kg)(v_2)

<u>v₂ = 5 m/s</u>

5 0
3 years ago
1 point
Kazeer [188]
P = m v
250 = m5

250 = 5m

m = 50 Kg

Option C
5 0
3 years ago
NEED HELP!!!! 15 POINTS!!!!
Nady [450]

Answer:

c

Explanation:

4 0
3 years ago
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