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Anika [276]
3 years ago
11

The average blood alcohol concentration (bac) of eight male subjects was measured after consumption of 15 ml of ethanol (corresp

onding to one alcoholic drink). The resulting data were modeled by the concentration function c(t) = 0.0225te−0.0467t
Chemistry
1 answer:
stiks02 [169]3 years ago
3 0

Answer:

The answer is 0.01365.

Explanation:

C(t) = 0.0225te^?0.0467t

We can derivate,

C'(t) = d/dt ( 0.0225 te^-0.0467t)

after solving,

C'(t) = 0.0225 (e^-0.0467t  - (0.0467e^-0.0467t . t)

Plug in t =5,

Answer is C'(t) = 0.01365.

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nalin [4]

The given molarity of sodium hydroxide solution = 2.0 M

The required concentration of sodium hydroxide is 65 mL of 0.6 M NaOH

Converting 65 mL to L:

65mL*\frac{1L}{1000mL} =0.065L

Calculating the moles of NaOH in the final solution:

0.065L * \frac{0.6 mol}{L} =0.039mol

Finding out the volume of 2.0 M solution taken to prepare the final solution:

0.039 mol * \frac{1L}{2.0mol}=0.0195L*\frac{1000mL}{1L} =19.5mL

Therefore, 19.5 mL of 2.0 M NaOH solution and make it up to 65 mL to prepare 0.6 M NaOH solution.


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