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Elodia [21]
2 years ago
9

Suppose you have a 2.0 molar solution of sodium hydroxide (naoh), and you need 65 ml of 0.6 molar naoh. how should you make this

solution?
Chemistry
1 answer:
nalin [4]2 years ago
3 0

The given molarity of sodium hydroxide solution = 2.0 M

The required concentration of sodium hydroxide is 65 mL of 0.6 M NaOH

Converting 65 mL to L:

65mL*\frac{1L}{1000mL} =0.065L

Calculating the moles of NaOH in the final solution:

0.065L * \frac{0.6 mol}{L} =0.039mol

Finding out the volume of 2.0 M solution taken to prepare the final solution:

0.039 mol * \frac{1L}{2.0mol}=0.0195L*\frac{1000mL}{1L} =19.5mL

Therefore, 19.5 mL of 2.0 M NaOH solution and make it up to 65 mL to prepare 0.6 M NaOH solution.


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(21.0 g Cl₂/ 70.906 g/mol Cl₂) x 2 mol AlCl₃/ 2 mol Cl₂ = 0.1974 mol AlCl₃

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