Question

Suppose you have a 2.0 molar solution of sodium hydroxide (naoh), and you need 65 ml of 0.6 molar naoh. how should you make this solution?

Answer 1

The given molarity of sodium hydroxide solution = 2.0 M

The required concentration of sodium hydroxide is 65 mL of 0.6 M NaOH

Converting 65 mL to L:

$65mL*\frac{1L}{1000mL} =0.065L$

Calculating the moles of NaOH in the final solution:

$0.065L * \frac{0.6 mol}{L} =0.039mol$

Finding out the volume of 2.0 M solution taken to prepare the final solution:

$0.039 mol * \frac{1L}{2.0mol}=0.0195L*\frac{1000mL}{1L} =19.5mL$

Therefore, 19.5 mL of 2.0 M NaOH solution and make it up to 65 mL to prepare 0.6 M NaOH solution.