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3 years ago

State boyl"s law and Charle's law

Chemistry

1 answer:

zubka84 [21]3 years ago

6 0

Answer:

hey mateee

Boyle's law :- the pressure (p) of a given quantity of gas varies inversely with its volume (v) at constant temperature.

Boyle's law can also be formularized as P1V1 = P2V2

Charle's law :- the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature, if the pressure remains constant.

Charle's law can also be formularized as V1/T1 = V2/T2

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Explanation:

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(1 atm = 760 Torr)

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n = number of moles of hydrogen gas= ?

R = Gas constant = 0.0821 L.atm/mol.K

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Putting values in above equation, we get:

Using an ideal gas equation:

$PV=nRT$

$n=\frac{PV}{RT}=\frac{0.98 atm\times 11 L}{0.0821 L atm/mol K\times 300.15 K}$

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Reactives -> Products

CuO and water are products.

I found this reaction which has CuO and water as products: decomposition of Cu(OH)2.

Cu(OH)2 -> CuO + H2O

Stoichiometry calculus involve the mole proportions you can see in the reaction: When 1 mole of Cu(OH)2 reacts, 1 mole of CuO and 1 mole of H2O are formed.

Considering the molar masses:

Cu(OH)2 = 83.56 g/mol

CuO = 79.545 g/mol

H2O = 18.015 g/mol

Then: When 83.56 g of Cu(OH)2 react, 79.545 g of CuO and 18.015 g H2O are formed.

You should use that numbers in the rule of three:

79.545 g CuO __________18.015 g water

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State boyl"s law and Charle's law​

State boyl"s law and Charle's law