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RoseWind [281]
3 years ago
13

You are trying to make balloon sculptures. You twist the balloons gently, but they keep popping. Besides trimming your nails, ho

w could you you prevent that? Why will your strategy work?
Chemistry
2 answers:
Maurinko [17]3 years ago
7 0

Answer:

              By decreasing pressure.

Explanation:

                      In order to prevent balloons from popping while making sculptures, it is suggested to decrease the pressure of air in parent  balloon. Decreasing the pressure of parent balloon will allow it to twist easily and make designs.

This strategy will work according to Boyle's Law which states that, "Pressure and Volume are inversely proportional to each  other at constant temperature".

Mathematically,

                                       P ∝ 1/V

Or,

                                       P = k/V

Or,

                                       PV = k

Hence, as the new designs made after twisting are of less volume, therefore it is good to decrease the pressure in advance otherwise the resulting less volume will increase the pressure of daughter small balloons  and will explode them.

blondinia [14]3 years ago
6 0
I would simply remove some air from the balloons because with less air pressure the balloons will be less tight and more twistable without popping so by doing this it will be possible to sculpt the balloons into varied shapes successfully.
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The atomic nucleus contains?
ycow [4]
The nucleus, that dense central core of the atom, contains both protons and neutrons. Electrons are outside the nucleus in energy levels. Protons have a positive charge,neutrons have no charge, and electrons have a negative charge. A neutral atom contains equal numbers of protons and electrons.
8 0
3 years ago
at atmoshperic pressure, a balloon contains 2.00L of nitrogen of gas. How would the volume change if the Kelvin temperature were
Nataly [62]

<u>Answer:</u> The percent change in volume will be 25 %

<u>Explanation:</u>

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=2L\\T_1=T_1\\V_2=?\\T_2=75\% \text{ of }T_1=0.75\times T_1

Putting values in above equation, we get:

\frac{2L}{T_1}=\frac{V_2}{0.75\times T_1}\\\\V_2=\frac{2\times 0.75\times T_1}{T_1}=1.5L

Percent change of volume = \frac{\text{Change in volume}}{\text{Initial volume}}\times 100

Percent change of volume = \frac{(2-1.5)}{2}\times 100=25\%

Hence, the percent change in volume will be 25 %

5 0
2 years ago
What is the answer?
rosijanka [135]
A generator because they connect each other in physical attraction
7 0
2 years ago
Read 2 more answers
Which of the following best explain why argon, which is a noble gas, does not react with other elements. Noble gases ________. A
S_A_V [24]

Answer:

D)

Explanation:

because they have completely filled and stable electron shells. Using you periodic table, it can show you that the noble gases are furthest to the right and explain the way outer shells of electrons work.

have a good day :)

7 0
2 years ago
A sample weighing 3.110 g is a mixture of Fe 2 O 3 (molar mass = 159.69 g/mol) and Al 2 O 3 (molar mass = 101.96 g/mol). When he
grandymaker [24]

Answer:

The mass fraction of ferric oxide in the original sample :\frac{723}{3110}

Explanation:

Mass of the mixture = 3.110 g

Mass of Fe_2O_3=x

Mass of Al_2O_3=y

After heating the mixture it allowed to react with hydrogen gas in which all the ferric oxide reacted to form metallic iron and water vapors where as aluminum oxide did not react.

Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)

Mass of mixture left after all the ferric oxide has reacted = 2.387 g

Mass of mixture left after all the ferric oxide has reacted = y

x=3.110 g- y=3.110 g - 2.387 g = 0.723 g

The mass fraction of ferric oxide in the original sample :

\frac{0.723 g}{3.110 g}=\frac{723}{3110}

5 0
3 years ago
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