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weqwewe [10]
3 years ago
8

Wat is a redox reaction

Chemistry
1 answer:
Ipatiy [6.2K]3 years ago
6 0

Answer:

A redox reaction is a form of chemical reaction requiring electron transfer between two organisms. It is any chemical reaction in which by gaining or losing an electron, the oxidation number of a particle, atom, or ion increases.

Explanation:

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The average human lives 74 years. how many seconds is this? write your answer in scientific notation
Leviafan [203]

Number of second in human lives in scientific notation is 3.9 × 10⁷ second

<u>Given that;</u>

Average human lives = 74 years

<u>Find:</u>

Number of second in human lives in scientific notation

<u>Computation:</u>

Number of second in human lives in scientific notation = 74 × 365 × 24 × 60

Number of second in human lives in scientific notation = 38,894,400

Number of second in human lives in scientific notation = 3.9 × 10⁷ second

Learn more:

brainly.com/question/3712546?referrer=searchResults

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I have to draw a diagram of the ingredient's particles in a pancake. E.g milk eggs etc the diagram must include what the particl
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4 0
3 years ago
Use the graph to answer these questions. The total energy of the reactants is –3,811.92 kJ. –1,273.02 kJ. –2,538.90 kJ.
TEA [102]

Answer:

the first one

Explanation:

8 0
3 years ago
Read 2 more answers
GIVING BRAINLIEST One mole of hydrogen gas (H2), reacts with one mole of bromine Br2(g) to produce 2 moles of hydrogen bromide g
JulsSmile [24]

Answer:

The equation to show the the correct form to show the standard molar enthalpy of formation:

\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ

Explanation:

The standard enthalpy of formation or standard heat of formation of a compound is the change of enthalpy during the formation of 1 mole of the substance from its constituent elements, with all substances in their standard states.

Given, that 1 mole of H_2 gas and 1 mole of Br_2 liquid gives 2 moles of HBr gas as a product.The reaction releases 72.58 kJ of heat.

H_2(g) + Br_2(l)\rightarrow 2HBr(g) ,\Delta H_{f}^o= -72.58kJ

Divide the equation by 2.

\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ

The equation to show the the correct form to show the standard molar enthalpy of formation:

\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ

4 0
3 years ago
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