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katen-ka-za [31]
3 years ago
13

Malia was able to make a paperclip float on the surface of water. What will most likely happen to the paperclip if a drop of dis

hwashing detergent is added near it?
Soap is a surfactant that increases the intermolecular forces of water allowing the paperclip to continue to float.
Soap makes the water less viscous making the paperclip sink.
Soap is a surfactant that disrupts the intermolecular forces of water making the paperclip sink.
Soap makes the water more viscous allowing the paperclip to continue to float.
Chemistry
1 answer:
Arturiano [62]3 years ago
5 0

Answer:

Its A

Explanation:

I just took the test

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The correct answer is H2SO3 I took the assignment already


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3 years ago
What is the term for an object's strength of motion?
Andrei [34K]

I'm pretty sure its momentum

3 0
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Derive third law of thermodynamics equation
Hoochie [10]

Answer:

The Third Law of thermodynamics states that the entropy of a pure substance in a perfect crystalline state at zero temperature is zero.

3 0
2 years ago
What is the complete balanced equation for the reaction that occurs when lithium carbonate (Li2CO3) is heated?
Fed [463]
When heating lithium carbonate (Li2CO3), it will dissociate to Li2O and Co2. So the balanced chemical equation of this reaction is Li2CO3 = Li2O + CO2. 
7 0
3 years ago
Information-
tekilochka [14]

Answer:

So first thing to do in these types of problems is write out your chemical reaction and balance it:

Mg + O2 --> MgO

Then you need to start thinking about moles of Magnesium for moles of Magnesium Oxide. Based on the above equation 1 mole of Magnesium is needed to make one mole of Magnesium Oxide.

To get moles of magnesium you need to take the grams you started with (.418) and convert to moles by dividing by molecular weight of Mg (24.305), this gives you .0172 moles of Mg.

The theoretical yield would be the assumption that 100% of the magnesium will be converted into Magnesium Oxide, so you would get, based on the first equation, .0172 mol of MgO. Multiplying this by the molecular weight of MgO (24.305+16) gives us .693 g of MgO.

The percent yield is what you actually got in the experiment, and for this you subtract off the total mass from the crucible mass, or 27.374 - 26.687, which gives .66 g of MgO obtained.

Percent yield is acutal/theoretical, .66/.693, or 95.24%.

I'll let you do the same for the second trial, and average percent yield is just an average of the two trials percent yield.

Hope this helps.

6 0
3 years ago
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