There are many compounds that contribute to the overall aroma of a banana. The primary compound is called isoamyl acetate and co
nsist of 60.58% C, 7.07% H, and 32.28%O. What is the empirical formula
1 answer:
Explanation:
Let the mass of isoamyl acetate be 100g.
Moles of Carbon = 60.58/12 = 5.048mol
Moles of Hydrogen = 7.07/1 = 7.07mol
Moles of Oxygen = 32.28/16 = 2.018mol
Mole Ratio of C : H : O
= 5.048 : 7.07 : 2.018
= 5 : 7 : 2.
Hence the empirical formula of isoamyl acetate is C5H7O2.
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