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Nadusha1986 [10]

2 years ago

11

Help idk how to do this

1 answer:

maksim [4K]2 years ago

8 0

Answer:

Explanation:

so we have to solve it or just answer it?

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A gas is contained in a thick-walled balloon. When the pressure changes from 45.0 bar to 96.0 bar, the volume changes from 1.20

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P1 * V1 ÷ T1 = P2 * V2 ÷ T2

45 * 1.20 ÷ 314 = 96 * V2 ÷ 420

30,144 * V2 = 22,680

V2 = 22,680 ÷ 30,144

The new volume is approximately 0.75 liter.

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A solution is diluted by adding more _____, which means the _____ of the solution increases but the amount (moles) of solute sta

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2 years ago

You wish to make 250. mL of 0.20 M KCl from a stock solution of 1.5 M KCl and DI water.

Nitella [24]

The question requires us to use the dilution formula $M_iV_i=M_fV_f$ , where $M_i$ and $V_i$ are the stock concentration and volume respectively, then $M_f$ and $V_f$ are the dilute concentration and volume respectively.

a. $C_s_t_o_c_k$ = 1.5 M KCI, $C_d_i_l_u_t_e$ =0.20M KCl, $V_d_i_l_u_t_e$ =250ml KCl

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To prepare the solution 33.3ml of 1.5M KCl is diluted to a total final volume of 250ml.

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3 years ago